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Nookie1986 [14]

3 years ago

5

A standard deck of playing cards contains 52 cards, equally divided among four suits(hearts, diamonds, clubs, and spades). Each

suit has the cards 2 through 10, as well as a jack, a queen, a kind, and an ace.
If the 3 of spades card is drawn from a standard deck and is not replaced, what is the probability that the next card drawn is a spade OR a kind?

A) $\frac{1}{17}$

B) $\frac{16}{51}$

C) $\frac{4}{17}$

D) $\frac{5}{17}$

1 answer:

Temka [501]3 years ago

3 0

Answer:

4/17

Step-by-step explanation:

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Seventeen people have been exposed to a particular disease. Each one independently has a 40% chance of contracting the disease.

docker41 [41]

Answer: the probability that the hospital's capacity will be exceeded = 0.035

Step-by-step explanation:

Shown in the attachment.

7 0

3 years ago

The sum of a number and its square is 182. Find the number.

Mars2501 [29]

Answer:

13 and -14 satisfy this condition

Step-by-step explanation:

Let's represent that number as x

and the square of x is x^2

So,

x + x^2 = 182

Subtract 182 from both sides

x + x^2 - 182 = 182 - 182

x + x^2 - 182 = 0

rearrange the quadratic equation

x^2 + x -182 = 0

let's use the quadratic formula

$\frac{-b+\sqrt{b^2-4ac} }{2a}$ or $\frac{-b-\sqrt{b^2-4ac} }{2a}$

a = 1, b = 1, c = -182

$\frac{-1+\sqrt{1^2-4*1*(-182)} }{2*1}$ or $\frac{-1-\sqrt{1^2-4*1*(-182)} }{2*1}$

$\frac{-1+\sqrt{1+728} }{2}$ or $\frac{-1-\sqrt{1+728} }{2}$

$\frac{-1+\sqrt{729} }{2}$ or $\frac{-1-\sqrt{729} }{2}$

$\frac{-1+{27} }{2}$ or $\frac{-1-{27} }{2}$

$\frac{26}{2}$ or $\frac{-28}{2}$

13 or - 14

Lets check

13 + 13^2 = 13 + 169

= 182

Also,

-14 + (-14^2) = -14 + 196

= 182

8 0

3 years ago

Accuracy in taking orders at a drive-through window is important for fast-food chains. Periodically, QSR Magazine publishes "The

pav-90 [236]

Answer:

a) 0.7412 = 74.12% probability that all the three orders will be filled correctly.

b) 0.0009 = 0.09% probability that none of the three will be filled correctly

c) 0.0245 = 2.45% probability that at least one of the three will be filled correctly.

d) 0.9991 = 99.91% probability that at least one of the three will be filled correctly

e) 0.0082 = 0.82% probability that only your order will be filled correctly

Step-by-step explanation:

For each order, there are only two possible outcomes. Either it is filled correctly, or it is not. Orders are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The percentage of orders filled correctly at Burger King was approximately 90.5%.

This means that $p = 0.905$

You and 2 friends:

So 3 people in total, which means that $n = 3$

a. What is the probability that all the three orders will be filled correctly?

This is P(X = 3).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{3,3}.(0.905)^{3}.(0.095)^{0} = 0.7412$

0.7412 = 74.12% probability that all the three orders will be filled correctly.

b. What is the probability that none of the three will be filled correctly?

This is P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{3,0}.(0.905)^{0}.(0.095)^{3} = 0.0009$

0.0009 = 0.09% probability that none of the three will be filled correctly.

c. What is the probability that one of the three will be filled correctly?

This is P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{3,1}.(0.905)^{1}.(0.095)^{2} = 0.0245$

0.0245 = 2.45% probability that at least one of the three will be filled correctly.

d. What is the probability that at least one of the three will be filled correctly?

This is

$P(X \geq 1) = 1 - P(X = 0)$

With what we found in b:

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0009 = 0.9991$

0.9991 = 99.91% probability that at least one of the three will be filled correctly.

e. What is the probability that only your order will be filled correctly?

Yours correctly with 90.5% probability, the other 2 wrong, each with 9.5% probability. So

$p = 0.905*0.095*0.095 = 0.0082$

0.0082 = 0.82% probability that only your order will be filled correctly

7 0

3 years ago

Marr you made 3 gallons of punch for a party when the party was over he had 3 quarts of punch left over how many quarts of punch

Inga [223]

The guest drank 9 quarts at the party

5 0

3 years ago

Part A Complete the stem and leaf plot for this data on the average cruising speeds of Red Eagle's planes.

kykrilka [37]

Answer:

hope this helps you. look it once

6 0

2 years ago