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Rina8888 [55]
2 years ago
14

2(x−3) = 2x + 15 how many solutions

Mathematics
1 answer:
sammy [17]2 years ago
5 0

Answer:

0

Step-by-step explanation:

2x-6=2x+15

2x-2x=15+6

0x/0=21/0

x=0

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Please help! How much is 840 miles in 3 & 1/2 hours?
Ilia_Sergeevich [38]

I'm assuming your teacher wants you to calculate the speed

1/2 = 0.5

3 & 1/2 = 3 + 1/2 = 3 + 0.5 = 3.5

If a plane flies 840 miles in 3.5 hours, then,

speed = distance/time

speed = (840 mi)/(3.5 hr)

speed = (840/3.5) mph

speed = 240 mph

<h3>Answer: 240 mph</h3>
7 0
2 years ago
Pls help find x in both
RUDIKE [14]

Answer:

Step-by-step explanation:

In similar triangles, corresponding sides are in same ratio

\frac{28}{24} = \frac{3x-9}{x +8}\\\\\frac{7}{6}=\frac{3x-9}{x+8}\\

Cross multiply,

7*(x + 8) = 6*(3x -9 )

7x + 7*8 = 6*3x - 6*9

7x +  56   = 18x - 54

          56 = 18x - 7x -54

          56 = 11x - 54

         11x - 54 = 56

               11x  = 56 +54

                11x = 110

               x = 110 /11

x = 10

PR = 3x -9

     = 30 - 9

PR = 21

8 0
3 years ago
The average speed of one team in a relay is about 5 miles per hour what is this speed in feet per second round to the nearest te
lisov135 [29]
50,802 is the answer cause you rounded
8 0
3 years ago
Assume that power surges occur as a Poisson process with rate 3 per hour. These events cause damage to a computer, thus a specia
lidiya [134]

Answer:

a) 0.30327

b) 0.07582

Step-by-step explanation:

This is a Poisson distribution problem

Poisson distribution probability function is given as

P(X = x) = (e^-λ)(λˣ)/x!

where λ = mean = 3 power surges per hour

x = variable whose probability is required

a) If a single disturbance in 10 minutes will crash the computer, what is the probability of the computer crashing, that is probability of a single disturbance (power surge) in 10 minutes?

λ = 3 disturbances per hour = 1 disturbance per 20 minutes = 0.5 disturbance per 10 minutes.

P(X = x) = (e^-λ)(λˣ)/x!

λ = 0.5 disturbance per 10 minutes

x = 1 disturbance per 10 minutes

P(X = 1) = (e^-0.5)(0.5¹)/1! = (e⁻⁰•⁵)(0.5)/1!

= 0.30327

b) If two disturbances in 10 minutes will crash the computer, what is the probability of the computer crashing, that is probability of two disturbances (power surges) in 10 minutes?

λ = 3 disturbances per hour = 1 disturbance per 20 minutes = 0.5 disturbance per 10 minutes.

P(X = x) = (e^-λ)(λˣ)/x!

λ = 0.5 disturbance per 10 minutes

x = 2 disturbance per 10 minutes

P(X = 2) = (e^-0.5)(0.5²)/2! = (e⁻⁰•⁵)(0.25)/2!

= 0.07582

Hope this Helps!!!

3 0
3 years ago
WILL GIVE BRAINLIST AND FIVE STARS IF ANSWER IS CORRECT FOR THIS!
Arada [10]

Answer:

5= initials times number of clothing

Step-by-step explanation:

5 0
3 years ago
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