Ask question

Ask question

All categories

2 years ago

9

Johnny’s monthly expenses and income are listed below. calculate johnny’s debt-to-income (dti) ratio. johnny's monthly debt and

income housing: rent $950.00 renter's insurance $25.00 credit: student $250.00 car $239.00 credit card

1 answer:

xxMikexx [17]2 years ago

8 0

Answer:

c

Step-by-step explanation:

You might be interested in

Solve the following systems by Elimination

Alenkasestr [34]

Answer:

The solutions for both system of equations are as follows:

(5,2)
(2,-1)

Step-by-step explanation:

The first set of equations is:

$4x+6y=32\\3x-6y=3\\$

It can clearly be seen that the coefficients of y are already same in magnitude with different signs so we have to add both equations

So adding both equations, we get

$4x+6y+3x-6y = 32+3\\7x = 35\\\frac{7x}{7} = \frac{35}{7}\\x = 5$

Putting x=5 in equation 1

$4(5)+6y = 32\\20+6y = 32\\6y = 32-20\\6y = 12\\\frac{6y}{6} = \frac{12}{6}\\y = 2$

The solution is (5,2)

The second set of simultaneous equations is:

$-3x+5y=-113x+7y=-1$

We can see that the coefficients of x in both equations are same in magnitude with opposite signs so

Adding both equations

$-3x+5y+3x+7y = -11-1\\12y = -12\\\frac{12y}{12} = \frac{-12}{12}\\y = -1$

Putting y= -1 in first equation

$-3x+5(-1)=-11\\-3x-5=-11\\-3x=-11+5\\-3x=-6\\\frac{-3x}{-3} = \frac{-6}{-3}\\x = 2$

The solution is: (2,-1)

Hence,

The solutions for both system of equations are as follows:

(5,2)
(2,-1)

3 0

3 years ago

Please help if you want BRIANLEIST

Katen [24]

Answer:

where is the work i dont see it

Step-by-step explanation:

6 0

3 years ago

Can someone help me with this ???

Arisa [49]

The equation is
Y=-3/1 +2
Y-Intercept at (0,2)

3 0

3 years ago

0.25:1.5 in simplest form

Lelechka [254]

The answer should be
_
.16

3 0

3 years ago

The sum of three numbers is 26. Twice the first minus the second is the third less 2. The third is the second minus 3 times the

Agata [3.3K]

Let a, b, c represent the three numbers. The problem statement gives rise to three equations:

a +b +c = 26
2a -b = c -2
-3a +b = c

Adding the first two equations gives

... (a +b +c) +(2a -b) = (26) +(c -2)

... 3a +c = 24 +c . . . . . simplify

... 3a = 24 . . . . . . . . . . subtract c

... a = 8 . . . . . . . . . . . . divide by 3

Adding the second and third equations gives ...

... (2a -b) +(-3a +b) = (c -2) +(c)

... -a = 2c -2 . . . . simplify

... -6 = 2c . . . . . . add 2, substitute for a

... -3 = c . . . . . . . . divide by 2

Using the third equation we can find b.

... -3·8 +b = -3 . . . . substitute for a and c

... b = 21 . . . . . . . . .add 24

The numbers are 8, 21, -3.

_____

The method above is sort of "ad hoc", taking advantage of the numbers in this particular set of equations. You can use more formal methods of Gaussian elimination or Cramer's Rule to solve these by just following a procedure. Or, your graphing calculator can do it for you.

6 0

3 years ago