Write a recursive and explicit formula for each option.
Save a nickel on the first day of the month and then double the amount each day for a month
=> a1 =0.05
=> a2 = a1* 2 = 0.05*2
=> a3 = a2*2 = a1* 2*2
..............................................
=>recursive an = 
=> explicit an = 0.05*
Start their savings by saving $10 on the first day and then $10 each day of the month
=> a1 = 10
=> a2 = a1 + 10 = 20
=> a3 = a2 +10 = 20 +10 =30
........................................................
=> recursive an = 
=> explicit an = 10 + 10( n-1)
Hope it will find you well.
Step-by-step explanation:
f(x) = x² + 1, where x >= 0.
Let y be f(x).
=> y = x² + 1
=> x² = y - 1
=> x = √(y - 1) because x is non-negative.
Hence f^-1(x) = √(x - 1), where x >= 1.
Answer:
all real numbers or 
Step-by-step explanation:
since both f(x) and g(x) are polynomials, neither of them have restrictions on their domains. Since they can be defined for all real numbers. It's not like the square root which has a domain of (0, infinity), or log x which is defined only from (0, infinity). So adding these two polynomials would result in a domain of all real numbers.
Answer:
Median: 11
Mean: 12
Mode: none
Step-by-step explanation:
M A T H W A Y helps
Mode is something that is repeated multiple times
so
Answer:
Step-by-step explanation:
So let's think about what values you can take square root of...
anything but negative values!
So the first one is not correct because you can also take square root of 0,
squareroot of 0 is 0.
So because of this, C and D are both correct, E is correct because root x is an increasing function. B is incorrect because (0,0) is an intercept.
