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zepelin [54]
3 years ago
13

5 ogarithmic equation in exponential form: log(5k + 4) = 8r

Mathematics
1 answer:
alexandr1967 [171]3 years ago
7 0

Given:

\log (5k+4)=8r

To find:

The exponential form of given equation.

Solution:

We have,

\log (5k+4)=8r

According to the property of the logarithm,

\log_ax=y\Rightarrow x=a^y

Using the above property of the logarithm, we get

5k+4=10^{8r}        

Therefore, the required equation in exponential form is 5k+4=10^{8r}.

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21 years ago Alvin was 11 times older than Tomio. The sum of their present age is 54.
DaniilM [7]

Answer:

Not sure exactly what answer you are looking for. But I assume it is the ages of them. Their original ages would be Tomio - 1 year old, Alvin - 11 years old. Now, Tomio - 22, Alvin - 32

Step-by-step explanation:

1(tomio) x 11 = 11 (alvin) (add 21 to these)

22+32=54

hope that makes sense

6 0
2 years ago
Jorge’s monthly bill from his Internet service provider was $25. The service provider charges a base rate of $15 per month plus
Vinil7 [7]
Isnt it 10 hours because he was charged 25$ and he is charged 1 dllr per hour soo
The 15$ per month plus the 10hrs he used it which is 10$ then is 25$ soo he used it for 10hrs.
8 0
3 years ago
Help me pleaseeeeeeeeee
leonid [27]
A is the answer i think

if not then c
5 0
3 years ago
Find the iqr of 4 5 6 8 9 10 11 12
77julia77 [94]

Answer:

The interquartile range is 5.

Step-by-step explanation:

Ah, a throwback to interquartile range... let me help :)

4,5,6,8,9,10,11,12

First, you need to know how to use the IQR. The interquartile range is basically known as the process of subtracting the upper quartile and the lower quartile of a set of data. The lower quartile should be written as Q1, and the upper quartile would be labeled as Q3. This would make the midpoint (median) data set Q2, and the highest possible point would be labeled Q4. Next, you have to always understand what you are looking at. For example, let's split the set 5,6,7,8,9,10,11,12 into groups. 5 and 6 would be Q1, 7 and 8 would be Q2, 9 and 10 would be Q3, and last but not least, 11 and 12 would be labeled as Q4. Now take Q1 and subtract it from Q3 and that is how you get your IQR.



3 0
3 years ago
Read 2 more answers
4+8+12=3x8 the next equation is
MAXImum [283]

Answer:

True 24=24

Step-by-step explanation:

4+8+12=3x8

12+12=24

24=24

7 0
3 years ago
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