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Hitman42 [59]
2 years ago
14

Rewrite the expression using only positive exponents. Show your work.

Mathematics
2 answers:
kramer2 years ago
8 0

5^{-12} \cdot 32^{-3} \cdot 9^{-15}\\\\\\=\dfrac 1{5^{12}} \cdot \dfrac 1{32^3} \cdot \dfrac 1{9^{15}}\\\\\\=\dfrac 1{5^{12}} \cdot \dfrac 1{(2^5)^3}\cdot \dfrac 1{9^{15}}\\\\\\=\dfrac  1{5^{12} \cdot 2^{15} \cdot 9^{15} }\\\\\\=\dfrac 1{5^{12}\cdot 18^{15}}

Alexxx [7]2 years ago
8 0

Answer:

\boxed{ \dfrac{1}{5^{12}}  \times \dfrac{1}{32^{3}}  \times \dfrac{1}{9^{15}}}

Step-by-step explanation:

In this case, all the exponents are negative. To make them positive, take the term's reciprocal and change the exponents sign.

\implies 5^{-12} \times 32^{-3} \times 9^{-15}

<u>Changing the terms into it's reciprocal form:</u>

\implies \dfrac{1}{5^{-12}}  \times \dfrac{1}{32^{-3}}  \times \dfrac{1}{9^{-15}}

<u>Changing the signs of the exponent:</u>

\implies\boxed{ \dfrac{1}{5^{12}}  \times \dfrac{1}{32^{3}}  \times \dfrac{1}{9^{15}}}

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Jorge is asked to build a box in the shape of a rectangular prism. The maximum girth of the box is 20 cm. What is the width of t
MariettaO [177]

Answer:

The width of the box is 6.7 cm

The maximum volume is 148.1 cm³

Step-by-step explanation:

The given parameters of the box Jorge is asked to build are;

The maximum girth of the box = 20 cm

The nature of the sides of the box = 2 square sides and 4 rectangular sides

The side length of square side of the box = w

The length of the rectangular side of the box = l

Therefore, we have;

The girth = 2·w + 2·l = 20 cm

∴ w + l = 20/2 = 10

w + l = 10

l = 10 - w

The volume of the box, V = Area of square side × Length of rectangular side

∴ V = w × w × l = w × w × (10 - w)

V = 10·w² - w³

At the maximum volume, we have;

dV/dw = d(10·w² - w³)/dw = 0

∴ d(10·w² - w³)/dw = 2×10·w - 3·w² = 0

2×10·w - 3·w² = 20·w - 3·w² = 0

20·w - 3·w² = 0 at the maximum volume

w·(20 - 3·w) = 0

∴ w = 0 or w = 20/3 = 6.\overline 6

Given that 6.\overline 6 > 0, we have;

At the maximum volume, the width of the block, w = 6.\overline 6 cm ≈ 6.7 cm

The maximum volume, V_{max}, is therefore given when w = 6.\overline 6 cm = 20/3 cm  as follows;

V = 10·w² - w³

V_{max} = 10·(20/3)² - (20/3)³ = 4000/27 = 148.\overline {148}

The maximum volume, V_{max} = 148.\overline {148} cm³ ≈ 148.1 cm³

Using a graphing calculator, also, we have by finding the extremum of the function V = 10·w² - w³, the coordinate of the maximum point is (20/3, 4000/27)

The width of the box is;

6.7 cm

The maximum volume is;

148.1 cm³

5 0
3 years ago
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Answer:

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Step-by-step explanation:

Which fraction is it out of all of these 6/14,5/8,25/30,or 3/6?

to determine which fractions are greater than 1/2, convert the fractions to decimals

to convert to decimals, divide the numerator by the denominator

1/2 = 0.5  less than half

6/14 = 0.43 less than half

5/8 = 0.625 greater than half

25 / 30 = 0.83 greater than half

3 / 6 = 0.5 equal to half

4 0
3 years ago
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defon

Answer:

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3 0
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Oksana_A [137]

Answer:

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Step-by-step explanation:

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