Answer:
goodgydudufjdjdjdjdururirurur7rigjfifut
Step-by-step explanation:
goodghdhfudjdjsdhydydbsjshhdvrjeiid
Answer:
The probability that neither person is left-handed is 88.36%, that only one is left-handed is 5.64%, and that both are left-handed is 0.36%.
Step-by-step explanation:
Supposing that 6% of people are left handed and supposing two people are picked at random, to find the probability that 0, 1 or 2 people are left-handed, the following calculation must be performed:
100 - 6 = 94
0 left-handed people = 0.94 x 0.94 = 0.8836 = 88.36%
1 left-handed person = 0.94 x 0.06 = 0.0564 = 5.64%
2 left-handed people = 0.06 x 0.06 = 0.0036 = 0.36%
Therefore, the probability that neither person is left-handed is 88.36%, that only one is left-handed is 5.64%, and that both are left-handed is 0.36%.
99/10=9
You can give 10 friends 9 slices with 9 slices leftover
Answer:
31/55 × 111
Step-by-step explanation:
the first one is less than 111 because it contains the only fraction that is less than 1
31/55 equals about 0.56
55/55 = 1
55/31 equals about 1.77
31/31 = 1