A surveyor standing on top of a cliff found that the angle of depression of a boat as sea is 22°. if the top of the cliff is 15m
1 answer:
Answer:
From the photo above i interpreted the question and drew a triangle to make it easier to solve
Tan is used to solve the question as we were given opposite (as height of the cliff) and to find Adjacent ( the distance between the foot of the cliff to the boat)
Tan θ =Opp/Adj
Tan 22°=15/a
Cross Multiply
aTanθ=15°
Divide both sides by Tan 22
aTan22/Tan22 = 15/Tan 22
a = 15/Tan 22°
a = 37.13 m
Therefore the distance between the foot of the cliff to the boat is 37.13 metres
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Answer:
8
Step-by-step explanation:
Using the pythagorean theorem (Assuming the house's walls are perpindicular to the ground):
a^2+b^2=c^2
we can find that 3=a and 29=c
3^2+b^2=29^2
9+b^2=841
b^2=832
b=
b=
b=8
That is the height that the ladder will reach