Answer:
Point O is the center of the circle.
<u>Part (a)</u>
is a chord.
is a segment of the radius and is perpendicular to 
If a radius is perpendicular to a chord, it bisects the chord (divides the chord into two equal parts).
Therefore, 
<u>Part (b)</u>
If
was extended past point E to touch the circumference it would be a chord.
As
is perpendicular to
, it would bisect the chord, but as
is only a portion of a chord,
<u>does not</u> bisect
.
Therefore, there is no length equal to
.
To find the root, replace y with 0
X^2-12x+35=0
A=1 B=-12 C=35
B^2-4ac=(-12)^2 -4(1)(35)
=144 -140
=4
x=(-b+/- square root of b^2 -4ac) /over/ (2a)
Plug in the numbers
x=-(-12) sqr (-12)^2 4(1)(35) / (2)(1)
X=12 +/-sqr 4 / 2
Positive outcome
x=12 + sqr 4 / 2
x=12+2/2
x=7 <— this one
Negative outcome
x=12-2i/2
x=6-i
Vertex: (6,-1)
Answer:
a. 0.588
b. 0.0722
c. 4.576 sqft/sec
Step-by-step explanation:
Let b and h denote the base and height as indicated in the diagram. By pythagoras theorem,
because it is a right angle triangle.
It is given that 
Now differentiate (1) with respect to t (time) :


The minus sign indicates that the value of h is actually decreasing. The required answer is 0.588.
b. From the diagram, infer that
. When b = 8, then
.
Differentiate the above equation w.r.t t

c. The area of the triangle is given by
. Differentiating w.r.t t,

Plugging in b = 8, h = 13.856,
,
From the picture, we can see that ΔLSP and ΔLRN are similar, so corresponding sides are proportionate:
LN : LP = 28:12 = 7:3
Therefore, the LRN sides is 7/3 of the corresponding side of LSP.
Then, it states that the area of LSP = 50, and area of a triangle is (1/2)bh, so we set up the equation
Area of LSP = (1/2)bh = 50 ← Remember how the corresponding sides are 7/3 of LSP? Therefore, the area of LRN:
LRN = (1/2)(7b/3)(7h/3) ← Take out the 7/3 and multiply them together
= (49/9)(1/2)bh ← From LSP, we know that (1/2)bh = 50, so plug that in
= (49/9)*50 ≈ 272.222 units ²