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Anettt [7]
3 years ago
9

A family has ninenine children. if this family has exactly threethree boysboysâ, how many different birth and gender orders areâ

possible
Mathematics
1 answer:
Alenkasestr [34]3 years ago
7 0
This is the problem of how many permutations the set bbbgggggg has. The set has size n=9, and you choose p=3 boys.

You can calculate it as:

\binom{9}{3} = \frac{9!}{3! \cdot 6!} = \frac{362880}{6\cdot720} = 84


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3 years ago
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shutvik [7]
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8 0
2 years ago
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A) 172<br><br> b) 192<br><br> C) 212<br><br> D) 232
tigry1 [53]

Answer:

212

Step-by-step explanation:

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3 years ago
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Which proportion is correct?
Sonja [21]

Answer:

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Step-by-step explanation:

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5 0
2 years ago
X^2-7x=18<br><br> solve for x <br> please show work
zloy xaker [14]
So the answer is, x1=-2, x2=9
x^2-7x=18
x^2-7x-18=0
x^2+2x-9x-18=0
x*(x+2)-9(x+2)=0
(x+2)*(x-9)=o
x+2=0
x-9=0
X=-2
X=9
I hope u understand!
3 0
3 years ago
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