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a_sh-v [17]
2 years ago
9

Lisa cut out 36 paper snowflakes to decorate her room.

Mathematics
1 answer:
levacccp [35]2 years ago
7 0

Answer: 32

Step-by-step explanation:

We know that the original number of paper snowflakes was 36, plus 28 given by her brother. The new total would be 64 paper snowflakes and she only uses half of the paper snowflakes. The answer would be 32.

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√50 inrrational or rational
goldfiish [28.3K]

Answer:

it is irrational

Step-by-step explanation:

hav a nice dAY

7 0
3 years ago
Help please now i cant figure it out
12345 [234]

Answer:

a. \frac{-11}{24}

b. \frac{-3}{2} \\

c. \frac{31}{7}

d.  \frac{11}{16}

11, 3, 31, 11 = code

Step-by-step explanation:

a. \frac{-1}{6}\\ * 2\frac{3}{4} =

2\frac{3}{4} = \frac{4*2+3 }{4}=  \frac{11}{4}

\frac{-1}{6}\\ * \frac{11}{4} = \frac{-1*11}{6*4} = \frac{-11}{24}

b.  \frac{3}{16} / \frac{-1}{8} =

\frac{3}{16} * \frac{8}{-1} = \frac{3*8}{16*-1} \\ = \frac{24}{-16} = \frac{-3}{2} \\

c. \frac{-31}{56} * \frac{-8}{1} = \frac{31}{7} (you can reduce 8 & 56 by dividing by 8: 56/8=7 & -8/8= -1)

d. 1 \frac{7}{8} / 2\frac{8}{11} =

1 \frac{7}{8} = \frac{8*1+7}{8} = \frac{15}{8}

2\frac{8}{11} = \frac{11*2+8}{11} = \frac{30}{11}

\frac{15}{8} * \frac{11}{30} = \frac{11}{16} (you can reduce 15 & 30 by dividing by 15: 15/15=1 & 30/15 = 2)

4 0
3 years ago
Find the p-value: An independent random sample is selected from an approximately normal population with an unknown standard devi
vladimir1956 [14]

Answer:

(a) <em>p</em>-value = 0.043. Null hypothesis is rejected.

(b) <em>p</em>-value = 0.001. Null hypothesis is rejected.

(c) <em>p</em>-value = 0.444. Null hypothesis is not rejected.

(d) <em>p</em>-value = 0.022. Null hypothesis is rejected.

Step-by-step explanation:

To test for the significance of the population mean from a Normal population with unknown population standard deviation a <em>t</em>-test for single mean is used.

The significance level for the test is <em>α</em> = 0.05.

The decision rule is:

If the <em>p - </em>value is less than the significance level then the null hypothesis will be rejected. And if the <em>p</em>-value is more than the value of <em>α</em> then the null hypothesis will not be rejected.

(a)

The alternate hypothesis is:

<em>Hₐ</em>: <em>μ</em> > <em>μ₀</em>

The sample size is, <em>n</em> = 11.

The test statistic value is, <em>t</em> = 1.91 ≈ 1.90.

The degrees of freedom is, (<em>n</em> - 1) = 11 - 1 = 10.

Use a <em>t</em>-table t compute the <em>p</em>-value.

For the test statistic value of 1.90 and degrees of freedom 10 the <em>p</em>-value is:

The <em>p</em>-value is:

P (t₁₀ > 1.91) = 0.043.

The <em>p</em>-value = 0.043 < <em>α</em> = 0.05.

The null hypothesis is rejected at 5% level of significance.

(b)

The alternate hypothesis is:

<em>Hₐ</em>: <em>μ</em> < <em>μ₀</em>

The sample size is, <em>n</em> = 17.

The test statistic value is, <em>t</em> = -3.45 ≈ 3.50.

The degrees of freedom is, (<em>n</em> - 1) = 17 - 1 = 16.

Use a <em>t</em>-table t compute the <em>p</em>-value.

For the test statistic value of -3.50 and degrees of freedom 16 the <em>p</em>-value is:

The <em>p</em>-value is:

P (t₁₆ < -3.50) = P (t₁₆ > 3.50) = 0.001.

The <em>p</em>-value = 0.001 < <em>α</em> = 0.05.

The null hypothesis is rejected at 5% level of significance.

(c)

The alternate hypothesis is:

<em>Hₐ</em>: <em>μ</em> ≠ <em>μ₀</em>

The sample size is, <em>n</em> = 7.

The test statistic value is, <em>t</em> = 0.83 ≈ 0.82.

The degrees of freedom is, (<em>n</em> - 1) = 7 - 1 = 6.

Use a <em>t</em>-table t compute the <em>p</em>-value.

For the test statistic value of 0.82 and degrees of freedom 6 the <em>p</em>-value is:

The <em>p</em>-value is:

P (t₆ < -0.82) + P (t₆ > 0.82) = 2 P (t₆ > 0.82) = 0.444.

The <em>p</em>-value = 0.444 > <em>α</em> = 0.05.

The null hypothesis is not rejected at 5% level of significance.

(d)

The alternate hypothesis is:

<em>Hₐ</em>: <em>μ</em> > <em>μ₀</em>

The sample size is, <em>n</em> = 28.

The test statistic value is, <em>t</em> = 2.13 ≈ 2.12.

The degrees of freedom is, (<em>n</em> - 1) = 28 - 1 = 27.

Use a <em>t</em>-table t compute the <em>p</em>-value.

For the test statistic value of 0.82 and degrees of freedom 6 the <em>p</em>-value is:

The <em>p</em>-value is:

P (t₂₇ > 2.12) = 0.022.

The <em>p</em>-value = 0.444 > <em>α</em> = 0.05.

The null hypothesis is rejected at 5% level of significance.

5 0
3 years ago
Giving brainliest!!!!!!! Please be correct if you don’t know the answer don’t andwer
mars1129 [50]

Answer:

C

Step-by-step explanation:hope this helps have a great day =D

3 0
2 years ago
What is 233 x 234 ???
andre [41]

Answer:

the answer is 54522

Step-by-step explanation:

hope it helps

7 0
3 years ago
Read 2 more answers
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