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3 years ago

I am a rectangular, and my area is 80 squares inches. My width is 2 inches shorter than my length . What is muy perimeter ?

1 answer:

8 0

The area is 80. Since the width of the rectangle is 2 inches shorter, the width has to be 8 and the length is 10. To find the perimeter, you add all the sides of the shape. In this case, we would add 8, 8, 10, 10.

8 + 8 + 10 +10 = 36

So the answer is 36 inches.

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matrenka [14]

Answer:

$(x + 6)(x - 6)$

Step-by-step explanation:

Given

See attachment for soccer field

Required

The possible dimension of the field

From the attachment, we have:

$Area = x^2 - 36$

$Length = x +a$

$Width = x + b$

So, we have:

$Length * Width = Area$

This gives:

$(x + a)(x + b) = x^2 - 36$

Express 36 as 6^2

$(x + a)(x + b) = x^2 - 6^2$

Express as difference of two squares

$(x + a)(x + b) = (x + 6)(x - 6)$

Hence, the dimension is: $(x + 6)(x - 6)$

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Minchanka [31]

PEMDAS
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3 years ago

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Step-by-step explanation:

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3 years ago

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elena-s [515]

Answer:

B. $\overline A \overline C \cong \overline B \overline D$

Step-by-step explanation:

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Answer:

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