Answer:
C) 1,250
Step-by-step explanation:
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Equation: 50 is greater than or equal to 45 + .5(x)
x = amount of pictures you can send without going over your budget
subtract 45 from both sides. you are left with: 5 is greater than or equal to .5(x)
multiply both sides by 2. you are left with: 10 is greater than or equal to x
Answer: 10 is greater than or equal to x
Answer:
The answer is below
Step-by-step explanation:
Let s(t) represent the amount of salt in the tank at time t. Therefore:
ds / dt = (rate of salt flowing into the tank) - (rate of salt going out of the tank)
![\frac{ds}{dt}=[(0.08\ kg/L*6\ L/min)+(0.09\ kg/L*5\ L/min)]-(\frac{s\ kg}{1000\ L}*11\ L/min ) \\\\\frac{ds}{dt}=(0.48\ kg/min+0.45\ kg/min)-(\frac{11s}{1000}\ kg/min )\\\\\frac{ds}{dt}=0.93\ kg/min-\frac{11s}{1000}\ kg/min \\\\\frac{ds}{dt}=\frac{930-11s}{1000}\ kg/min \\\\\frac{ds}{930-11s}=\frac{1}{1000}dt\\\\Integrating:\\\\\int\limits { \frac{ds}{930-11s}} \, ds=\int\limits {\frac{1}{1000}} \, dt\\\\-\frac{1}{11}ln(930-11s)=\frac{t}{1000}+C\\\\multiply\ through\ by\ -11:](https://tex.z-dn.net/?f=%5Cfrac%7Bds%7D%7Bdt%7D%3D%5B%280.08%5C%20kg%2FL%2A6%5C%20L%2Fmin%29%2B%280.09%5C%20kg%2FL%2A5%5C%20L%2Fmin%29%5D-%28%5Cfrac%7Bs%5C%20kg%7D%7B1000%5C%20L%7D%2A11%5C%20L%2Fmin%20%29%20%5C%5C%5C%5C%5Cfrac%7Bds%7D%7Bdt%7D%3D%280.48%5C%20kg%2Fmin%2B0.45%5C%20kg%2Fmin%29-%28%5Cfrac%7B11s%7D%7B1000%7D%5C%20kg%2Fmin%20%29%5C%5C%5C%5C%5Cfrac%7Bds%7D%7Bdt%7D%3D0.93%5C%20kg%2Fmin-%5Cfrac%7B11s%7D%7B1000%7D%5C%20kg%2Fmin%20%5C%5C%5C%5C%5Cfrac%7Bds%7D%7Bdt%7D%3D%5Cfrac%7B930-11s%7D%7B1000%7D%5C%20kg%2Fmin%20%5C%5C%5C%5C%5Cfrac%7Bds%7D%7B930-11s%7D%3D%5Cfrac%7B1%7D%7B1000%7Ddt%5C%5C%5C%5CIntegrating%3A%5C%5C%5C%5C%5Cint%5Climits%20%7B%20%5Cfrac%7Bds%7D%7B930-11s%7D%7D%20%5C%2C%20ds%3D%5Cint%5Climits%20%7B%5Cfrac%7B1%7D%7B1000%7D%7D%20%5C%2C%20%20dt%5C%5C%5C%5C-%5Cfrac%7B1%7D%7B11%7Dln%28930-11s%29%3D%5Cfrac%7Bt%7D%7B1000%7D%2BC%5C%5C%5C%5Cmultiply%5C%20through%5C%20by%5C%20-11%3A)
![ln(930-11s)= - \frac{11t}{1000}+A\\\\Take \ exponential:\\\\930-11s=e^{ - \frac{11t}{1000}+A}\\\\930-11s=C_1e^{ - \frac{11t}{1000}}\\\\11s=930-C_1e^{ - \frac{11t}{1000}}\\\\s=\frac{930-C_1e^{ - \frac{11t}{1000}}}{11} \\\\To \ find\ C_1,s(0)=0.Hence:\\\\0=\frac{930-C_1e^{ - \frac{11(0)}{1000}}}{11} \\\\0=930-C_1\\\\C_1=930\\\\s(t)=\frac{930-930e^{ - \frac{11t}{1000}}}{11} \\\\s(t)=930(\frac{1-e^{ - \frac{11t}{1000}}}{11})](https://tex.z-dn.net/?f=ln%28930-11s%29%3D%20-%20%5Cfrac%7B11t%7D%7B1000%7D%2BA%5C%5C%5C%5CTake%20%5C%20exponential%3A%5C%5C%5C%5C930-11s%3De%5E%7B%20-%20%5Cfrac%7B11t%7D%7B1000%7D%2BA%7D%5C%5C%5C%5C930-11s%3DC_1e%5E%7B%20-%20%5Cfrac%7B11t%7D%7B1000%7D%7D%5C%5C%5C%5C11s%3D930-C_1e%5E%7B%20-%20%5Cfrac%7B11t%7D%7B1000%7D%7D%5C%5C%5C%5Cs%3D%5Cfrac%7B930-C_1e%5E%7B%20-%20%5Cfrac%7B11t%7D%7B1000%7D%7D%7D%7B11%7D%20%5C%5C%5C%5CTo%20%5C%20find%5C%20C_1%2Cs%280%29%3D0.Hence%3A%5C%5C%5C%5C0%3D%5Cfrac%7B930-C_1e%5E%7B%20-%20%5Cfrac%7B11%280%29%7D%7B1000%7D%7D%7D%7B11%7D%20%5C%5C%5C%5C0%3D930-C_1%5C%5C%5C%5CC_1%3D930%5C%5C%5C%5Cs%28t%29%3D%5Cfrac%7B930-930e%5E%7B%20-%20%5Cfrac%7B11t%7D%7B1000%7D%7D%7D%7B11%7D%20%5C%5C%5C%5Cs%28t%29%3D930%28%5Cfrac%7B1-e%5E%7B%20-%20%5Cfrac%7B11t%7D%7B1000%7D%7D%7D%7B11%7D%29)
Electric current is the movement of the electrons caused by potential
difference. For example, in a circuit, the electrons in the bulb will not move
without the potential difference or voltage. When there is voltage, electric
current occurs because there is a driving force for the electrons in the wire
to move.
Answer: it will be 3 feet high
Step-by-step explanation: what you do is read what it is asking you again and the answer is 3