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loris [4]
2 years ago
10

In the diagram below of parallelogram ABCD with diagonals AC and BD, m∠1=45° and m∠DCB=120°.Whatisthemeasureof∠2?

Mathematics
1 answer:
bixtya [17]2 years ago
5 0

Answer:

15degrees

Step-by-step explanation:

From the given diagram

<1+<2 + <DCB = 180

<1+<2+120 = 180

<1+<2 = 180 - 120

<1+<2 = 60

<2 = 60 - <1

<2 = 60 - 45

<2 = 15degrees

Hence the measure <2 is 15degree

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3a. y=\frac{3}{x-1}

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4c. y=\sqrt[3]{\frac{x-7}{3}}, y=3x^3+7
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