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Phoenix [80]
2 years ago
5

A store having a sale on chocolate chips

Mathematics
1 answer:
Nostrana [21]2 years ago
5 0

Answer:

chocolate chips: $3.75

walnuts: $2.5

Step-by-step explanation:

lets say chocolate chips cost x dollars and walnuts cost y dollars. we then have

6x + 5y = 35

2x + 3y = 15

multiply the second equation by 3 to get 6x + 9y = 45

subtract the 1st equation from the new equation to get 4y = 10, so y=$2.50

plug this value into the 2nd equation to get x=$3.75

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30 degrees is what the answer is because it says it in the question
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3 years ago
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9 hundred thousands equal how many tens
il63 [147K]
900,000=10*90,000

So there are 90,000 tens in 900,000.
5 0
3 years ago
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How do I do it and show my work along with it?
Rudiy27
Be kind and say please,that is being rude when you don't say it. Well, how much times does 6 go into 34? 5 times right. So then put 30 under the 34. You get 4. So then bring down the 5. How much times does 6 go into 45. 7 right. So then put 42 under 45. You get 3. Now add a decimal point after the 5 and after the 7. Add zero after the 5 . Bring down the zero. How much times does 6 go into 30? 5 times, so you put 30 under 30 and get zero. If you have any more questions,please leave them below in the comments.
8 0
3 years ago
A person on a runway sees a plane approaching. The angle of elevation from the runway to the plane is 11.1° . The altitude of th
Gnoma [55]

Answer:

The horizontal distance from the plane to the person on the runway is 20408.16 ft.

Step-by-step explanation:

Consider the figure below,

Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner.  The angle of elevation from the runway to the plane is 11.1°

BC is the horizontal distance from the plane to the person on the runway.

We have to find distance BC,

Using trigonometric ratio,

\tan\theta=\frac{Perpendicular}{base}

Here, \theta=11.1^{\circ} ,Perpendicular AB = 4000

\tan\theta=\frac{AB}{BC}

\tan 11.1^{\circ} =\frac{4000}{BC}

Solving for BC, we get,

BC=\frac{4000}{\tan 11.1^{\circ} }

BC=\frac{4000}{0.196} (approx)

BC=20408.16(approx)  

Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft

8 0
3 years ago
Finding it hard. I’d love some help and the answers. Thanks
nevsk [136]

for all of them its base times height

v=bh

1) (8*6/2)*9.5=228

2) (4.5/2)^2 *8= 40.5

3) (3.3* 8.3/2) *5.4= 74.0

4) ((3.2+4.8)/2)* 2.7 *4.4= 47.5

7 0
2 years ago
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