3 years ago

Find the length of the side of the square.

Mathematics

1 answer:

nignag [31]3 years ago

6 0

6x-1=4x+6

subtracting 4x from each side

2x-1=6

adding 1 to each side

2x=7

divide by 2

x=7/2 or 3.5

check: 6(7/2) -1 =4(7/2)+6

21-1 =14+6

20=20 correct

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3 years ago

Which is the simplified form of (9c^-9)^-3 b 1/729 c^27

rosijanka [135]

ANSWER

$(9 {c}^{ - 9} )^{ - 3}=\frac{{c}^{ 27} }{729}$

EXPLANATION

The given expression is

$(9 {c}^{ - 9} )^{ - 3}$

Recall that:

$({a}^{m} )^{n} = {a}^{mn}$

We use the law of exponents to get

$(9 {c}^{ - 9} )^{ - 3} = 9^{ - 3} {c}^{ - 9 \times - 3}$

Let us multiply in the exponents to get:

$(9 {c}^{ - 9} )^{ - 3} = 9^{ - 3} {c}^{ 27}$

Recall again that:

${a}^{ - m} = \frac{1}{ {a}^{m} }$

This implies that:

$(9 {c}^{ - 9} )^{ - 3} = \frac{1}{ {9}^{ 3} } \times {c}^{ 27}$

We expand the power to get:

$(9 {c}^{ - 9} )^{ - 3} = \frac{1}{9 \times 9 \times 9} \times {c}^{ 27}$

$(9 {c}^{ - 9} )^{ - 3}=\frac{1}{729} \times {c}^{ 27}$

We multiply out to get:

$(9 {c}^{ - 9} )^{ - 3}=\frac{{c}^{ 27} }{729}$

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