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3 years ago

Find the length of the side of the square.

Mathematics

1 answer:

nignag [31]3 years ago

6 0

6x-1=4x+6

subtracting 4x from each side

2x-1=6

adding 1 to each side

2x=7

divide by 2

x=7/2 or 3.5

check: 6(7/2) -1 =4(7/2)+6

21-1 =14+6

20=20 correct

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Consider that ΔQRS is similar to ΔLMN and the measure of ∠N is 42°. What is the measure of ∠S? A) 42° B) 48° C) 56° D) 58°

Veseljchak [2.6K]

Answer:

The answer is A) 42°

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2 years ago

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Emily took 300 US dollars to the bank to exchange it for Canadian dollars. The exchange rate on that day was 1.25 Canadian dolla

Paha777 [63]

Emily wanted to exchange her 300 US Dollars for Canadian Dollars.

The exchange rate for it was 1.25 Canadian Dollars for 1 US Dollar.

This means that 1 US Dollar = 1.25 Canadian Dollars.

So if we were to follow this pattern,

2 US Dollars = 2 × 1.25 = 2.5 Canadian Dollars

3 US Dollars = 3 × 1.25 = 3.75 Canadian Dollars

4 US Dollars = 4 × 1.25 = 5 Canadian Dollars

So for 300 US Dollars, we'll need to multiply 300 by 1.25.

300 US Dollars = 300 × 1.25 = 375 Canadian Dollars.

Hope it helps. :)

4 0

2 years ago

Helen plays basketball. For free throws, she makes the shot 78% of the time. Helen must now attempt two free throws. C = the eve

riadik2000 [5.3K]

Answer:

0.6708 or 67.08%

Step-by-step explanation:

Helen can only make both free throws if she makes the first. The probability that she makes the first free throw is P(C) = 0.78, now given that she has already made the first one, the probability that she makes the second is P(D|C) = 0.86. Therefore, the probability of Helen making both free throws is:

$P(C+D) = P(C) *P(D|C) = 0.78*0.86\\P(C+D) = 0.6708$

There is a 0.6708 probability that Helen makes both free throws.

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3 years ago

. Given that O is the centre of the following circle, find the values of the unknowns.

alex41 [277]

Given:

Radius of circle is 13 cm

Height of triangle is 5 cm

To find:

Value of 'a' and 'b'

Steps:

To find value of 'a', we will use Pythagoras theorem as the triangle is a right angle triangle,

A² + B² = C²

$a^{2} + 5^{2} = 13^{2}$

$a^{2} + 25 = 169$

$a^{2} = 169 - 25$

$a^{2} = 144$

$\sqrt{a^{2}}=\sqrt{144}$

$a = 12$

Now to find the value of 'b', i will use law of cosine,

$c=\sqrt{a^{2}+b^{2}-2ab(cos\beta ) }$

$12 = \sqrt{13^{2}+5^{2}-2(5)(13)(cos\beta )}\\12=\sqrt{169 + 25-130(cos\beta )}\\12=\sqrt{194-130(cos\beta )}\\144 = 194 - 130(cos\beta )\\50 = 130(cos\beta )\\cos\beta = 0.3846\\\beta = cos^{-1}(0.3846)\\\beta = 67.38$

Therefore, the values of 'a' and 'b' is 12 and 67.38 respectively

Happy to help :)

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3 0

2 years ago

1/2+(-5/8) please help me I really need help have a great day

daser333 [38]

Answer:

-0.125

Step-by-step explanation:

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3 years ago

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