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m_a_m_a [10]
2 years ago
9

A botanist records the height of a plant every day for a month. She wants to create a graph to show how the plant's height chang

ed over the month. What type of display should she use? Explain.
Mathematics
2 answers:
Ratling [72]2 years ago
8 0

Answer:

Scatter plot because, A simply X-Y axis line graph is a good choice for this. I hope I could help.

telo118 [61]2 years ago
7 0

They should use a SCATTER PLOT.

ʜᴏᴘᴇ ɪ ᴄᴏᴜʟᴅ ʜᴇʟᴘ —

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X = ?????? Geometry
adelina 88 [10]

Answer:

\boxed{x^2 = 16}

Step-by-step explanation:

Using Tangent Secant theorem:

(x)² = (2)(2+6)

x² = 2(8)

x² = 16

7 0
3 years ago
How will this be writen seven less than the quotient of nineteen and a number
maxonik [38]

19/n - 7 or (19/n) - 7

6 0
3 years ago
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What can you say about the relationship between M and P? Which letter is the correct answer?
Dimas [21]

Answer:

Choice C is correct

Step-by-step explanation:

The first step is to re-write the equations in exponential form.

The first equation can be written as;

\frac{M}{N}=10^{4} since the base is 10 and 4 the exponent.

The second equation can be written as;

\frac{P}{N}=10^{5}

The second step is to make N the subject of the formula in both equations.

Solving for N from this equation \frac{M}{N}=10^{4}, yields;

N=\frac{M}{10^{4}}

Solving for N from the second equation \frac{P}{N}=10^{5}, yields;

N=\frac{P}{10^{5}}

Therefore;

\frac{M}{10^{4}}=\frac{P}{10^{5} }\\\\P=10M

6 0
4 years ago
What is the equation of the quadratic graph with a focus of (3, 1) and a directrix of y = 5?
telo118 [61]

Answer:

f(x)=-\frac{1}{8}(x-3)^2+3

Step-by-step explanation:

We want to find the equation of the parabola with a focus of (3,1) and directrix y=5.

Considering the directrix, the quadratic graph must open downwards.


The equation of this parabola is given by the formula,

(x-h)^2=4p(y-k), where (h,k) is the vertex of the parabola.


The axis of this parabola meets the directrix at (3,5).

Since the vertex is the midpoint of the focus and the point of intersection of the axis of the parabola and the directrix,


h=\frac{3+3}{2}=3 and k=\frac{5+1}{2}=3.


The equation of the parabola now becomes,


(x-3)^2=4p(y-3).


Also |p| is the distance between the vertex and the directrix.


|p|=2


This implies that p=-2\:or\:2.


Since the parabola turns downwards,


p=-2.



Our equation now becomes,


(x-3)^2=4(-2)(y-3).


(x-3)^2=-8(y-3).


We make y the subject to get,

y=-\frac{1}{8}(x-3)^2+3).


This is the same as

f(x)=-\frac{1}{8}(x-3)^2+3).









4 0
3 years ago
What is 33% out of 50
Zolol [24]

Answer:

66

Step-by-step explanation:

5 0
3 years ago
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