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mestny [16]
3 years ago
13

Find the surface area of each figure. round your answer to the nearest tenth

Mathematics
1 answer:
qaws [65]3 years ago
8 0

Answer: 378.57mi²

Step-by-step explanation:

Formula = a²+2a√{(a²/4)+h²}

please click thanks and mark brainliest if you like :)

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Choose the answer that shows exponential decay?*
Vlad1618 [11]
I’m not sure what that is
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If John has 1107 bars of chocolate and wants to give each of his 10 friends an even amount each, what would each friend get? Wha
Nutka1998 [239]
Divide 1107 by 10, for example:

1107/10= 110.7

The decimal point means the remainder, this means John will only get 7 chocolate bars. 

If You want it split evenly between ALL of them, divide by 1107 by 11, for example: 

1107/11= 100.6, which would leave six bars left, so I think the logical offer would be the first answer I gave you. 

I hope this helped! 
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3 years ago
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Answer is B, the graph increases by about 0.28 per year
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3 years ago
If f(x)=x^2-7 and h(x)=7x-5, then f(h(2))=
zaharov [31]
We are given 3 equations. Using these equations we can find f(h(2)).

h(x)=7x-5
h(2)=7(2)-5
h(2)=14-5
h(2)=9

f(x)=x^2-7
f(h(2))=(7x-5)^2-7
we know the answer for h(2) by now, so we can substitute for that.
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5 0
3 years ago
The results of a swim <br> Wet are shown. Who swam faster explain your reasoning
kolbaska11 [484]

Answer:

The Susana swam the fastest.

Step-by-step explanation:

<u>Speed</u> : It is defined as the distance traveled per unit time.

<u>Formula used</u> : Speed = \frac{Distance}{Time}

First we have to determine speed of the following persons.

<u>For Tawni :</u>

Distance = 50 m

Time = 40.8 s

1.225 m/s which is the speed of Tawni.

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<u>For Pepita :</u>

Distance = 100 m

Time = 60.2 s

1.661 m/s which is the speed of Pepita

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<u>For Susana :</u>

Distance = 200 m

Time = 112.4 s

1.779 m/s which is the speed of Susana

From this we conclude that, in this problem meter affects the response and the speed of Susana is more than the Pepita and Tawani.

Thus, Susana swam the fastest.

7 0
3 years ago
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