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2 years ago

Find the surface area of each figure. round your answer to the nearest tenth

Mathematics

1 answer:

qaws [65]2 years ago

8 0

Answer: 378.57mi²

Step-by-step explanation:

Formula = a²+2a√{(a²/4)+h²}

please click thanks and mark brainliest if you like :)

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A single card is drawn from a standard 52 card deck.

Alecsey [184]

Answer:

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2 years ago

Can someone help me with this

Art [367]

Ans57 , 58 , 59

Step-by-step explanation:

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1 year ago

What is the remainder of 3,368,008 divided by 5574<br><br> I'm looking for the REMAINDER

Mkey [24]

I think it might be

3,362,461

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2 years ago

Someone plz help me with this

Phoenix [80]

Answer:

$5y^{6}\sqrt{2}$

Step-by-step explanation:

We want to simplify:

$\sqrt{50y^{12}}$

We rewrite as:

$\sqrt{2\times25 \times (y^{6})^2}$

We split the radical sign to obtain:

$\sqrt{25} \times \sqrt{(y^{6})^2} \times \sqrt{2}$

Simplify the square root for the perfect squares to get:

$5y^{6}\sqrt{2}$

Therefore the simplified form is: $5y^{6}\sqrt{2}$

8 0

2 years ago

a group of astronauts launched a model rocket from a platform. Its flight path is modeled by h= -4t^2+24t+13 where h is the heig

Eddi Din [679]

Answer:

6.5 seconds

Step-by-step explanation:

Keep in mind that when $h=0$ , this is the same height for both when the model rocket takes off and lands, so when the rocket lands, time is positive. Thus:

$h=-4t^2+24t+13\\\\0=-4t^2+24t+13\\\\t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\ \\t=\frac{-24\pm\sqrt{24^2-4(-4)(13)}}{2(-4)}\\ \\t=\frac{-24\pm\sqrt{576+208}}{-8}\\\\t=\frac{-24\pm\sqrt{576+208}}{-8}\\\\t=\frac{-24\pm\sqrt{784}}{-8}\\\\t=\frac{-24\pm28}{-8}\\\\t=\frac{-24-28}{-8}\\ \\t=\frac{-52}{-8}\\ \\t=\frac{52}{8}\\\\t=6.5$

So, the amount of seconds that the model rocket stayed above the ground since it left the platform is 6.5 seconds

5 0

2 years ago

Read 2 more answers