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2 years ago

9

[100 points]

1 answer:

Veronika [31]2 years ago

8 0

Answer:

Multiply the moduli and add the arguments.Step-by-step explanation:First write out the two terms being multiplied: z1z2= [r1(cos(theta 1) + isin(theta 1))][r2(cos(theta 2)+ isin(theta 2))] z1z2= r1r2 (cos(theta 1) + isin(theta 1))(cos(theta 2)+ isin(theta 2)) z1z2= r1r2(cos(theta 1)cos(theta 2))+(icos(theta 1)sin(theta 2))+(icos(theta 2)sin(theta 1))+(i^2 sin(theta 1)sin(theta 2)) Next group and rewrite the like term with the sums and differences. Your answer is the multiplication of the moduli and the addition of the arguments: z1z2= r1r2[cos(theta 1 + theta 2) + i sin (theta 1 and theta 2)].

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Radda [10]

Answer:

15<em>y</em> = -28 <em>x</em> + 205.

Step-by-step explanation:

Slope intercept form of equation is <em>y = mx + c</em> where m is slope and c is the y intercept.

Now slope of line passing through points (-5, 23) and (10, -5):

$m = \frac{y_{2} - y_{1} }{x_{2} - x_{1} } = \frac{-5 -23}{10 + 5} = \frac{-28}{15}$

Now equation of line:

<em> y = mx + c</em>

substituting the value of m in above expression,

$y = -\frac{28}{15} x + c$

Now, since the line is passing through the point (-5, 23) therefore, x = -5 and y = 23. By substituting these values in above equation,

$23 = -\frac{28}{15} \times (-5) + c$

$23 = \frac{28}{3} + c$

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✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

Hello!

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❖ The area is 169 square cm.

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13 x 13 = 139

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