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2 years ago

PLEASE HELP!

Mathematics

1 answer:

Bumek [7]2 years ago

5 0

Answer:Yes.

Step-by-step explanation: Substitute either of the those values and you should get the other.

For instance, substituting x = 1 got you y = 5. If you had substituted x = 1 and got a different y-value, then the coordinates would have been incorrect.

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True or False? A right triangle can have a leg measuring 10cm and a hypotenuse measuring 10cm

Citrus2011 [14]

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2 years ago

Which value is NOT a solution of 8x3 – 1 = 0?

Tpy6a [65]

<u><em>Note: As you may have unintentionally missed to add the value choices. But, I would make sure to explain the concept so that you may improve your understanding in terms of solving these type of questions.</em></u>

Answer:

Any value other than the values $x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$ will not be a solution of $8x^3\:-\:1\:=\:0$ .

Step-by-step explanation:

Considering the equation

$8x^3\:-\:1\:=\:0$

Steps to solve the equation

$8x^3-1=0$

$\mathrm{Add\:}1\mathrm{\:to\:both\:sides}$

$8x^3-1+1=0+1$

$\mathrm{Simplify}$

$x^3=\frac{1}{8}$

$\mathrm{Divide\:both\:sides\:by\:}8$

$\frac{8x^3}{8}=\frac{1}{8}$

$\mathrm{Simplify}$

$x^3=\frac{1}{8}$

$\mathrm{For\:}x^3=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}$

$x=\sqrt[3]{\frac{1}{8}},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1+\sqrt{3}i}{2},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1-\sqrt{3}i}{2}$

So,

$x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$

Therefore,

Any value other than the values $x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$ will not be a solution of $8x^3\:-\:1\:=\:0$ .

Keywords: solution, value

Learn more about equation solution from brainly.com/question/1679491

#learnwithBrainly

7 0

2 years ago

Identify the x-intercept

sveta [45]

im quite positive that the x-intercept is 1,6

8 0

2 years ago

Reduce 36/45 to lowest terms and write the numerator in the blank.

saveliy_v [14]

4/5 is your answer

Hope this helps

7 0

3 years ago

Read 2 more answers

In what time will Rs. 5600 amount to Rs. 6720 at 8% per annum?

Leona [35]

Answer: 2 years

Step-by-step explanation:

If Interest= Principal x rate x time/100; then time is (100 × Interest)/(Principal × Rate)

From the question, old Principal is 5600, new principal =6720, the difference is the interest accrued.

Interest = 6720 - 5600 = Rs 1120

Rate = 8% = 8 ÷ 100 = 0.08

Time = x

Then, slot the values into the formula

Time= 100 x 1120 / 6720 x 8

= 112000/53760

=2.08

Time= 2years

I hope this helps

8 0

3 years ago