The LCD of the denominator is 12. For this one it is possible to just 'see' that 6 is a divisor of 12. When in doubt, you can always get an answer by just multiplying the denominators. (ie., you can turn 11/12 into 66/72 and 1/6 into 12/72).
In this case, the easiest is to convert 1/6 into 2/12. (multiply both numbers by 2).
Then it becomes:
Answer:
Feet Above Sea Level
Step-by-step explanation:
A benchmark is a term in Surveying and Geo informatics, that describes a point of reference established at a known elevation which serves as basis in which other elevation or topographical point can be measured.
Therefore, when determining the benchmark, it's height is calculated relative to the vertical datum of the area, typically mean sea level, which is then recorded in FEET ABOVE SEA LEVEL.
Hence, Benchmarks measurements refer to FEET ABOVE SEA LEVEL.
Answer:
90 - 55 = 35
its 35
Step-by-step explanation:
Answer:
11
Step-by-step explanation:
198 ÷ 18 = 11
x = 11
......
Quantify of sand in a bag =



Quantity of sand that escapes in every 10 minutes :-

Quantity of sand that will escape in 20 minutes :-




Quantity of sand that will remain in the sand bag :-





