Answer:
The probability that at least 1 car arrives during the call is 0.9306
Step-by-step explanation:
Cars arriving according to Poisson process - 80 Cars per hour
If the attendant makes a 2 minute phone call, then effective λ = 80/60 * 2 = 2.66666667 = 2.67 X ≅ Poisson (λ = 2.67)
Now, we find the probability: P(X≥1)
P(X≥1) = 1 - p(x < 1)
P(X≥1) = 1 - p(x=0)
P(X≥1) = 1 - [ (e^-λ) * λ^0] / 0!
P(X≥1) = 1 - e^-2.67
P(X≥1) = 1 - 0.06945
P(X≥1) = 0.93055
P(X≥1) = 0.9306
Thus, the probability that at least 1 car arrives during the call is 0.9306.
Answer:
Solution
Correct option is C)
(fog)(x)=f(g(x))=2(3x+2)−1=6x+4−1=6x+3=3(2x+1)
Answer:
12 miles
Step-by-step explanation:
There are 3 hours = 180 minutes
180÷30=6
6×2=12
Hope that helps!
Answer:
<u>c = 10 - 11(0.65)</u>
Step-by-step explanation:
The equation is :
<u />
Change will be :
Answer:
The value of the test statistic 
Step-by-step explanation:
From the question we are told that
The high dropout rate is 
% 
The sample size is 
The number of dropouts 
The probability of having a dropout in 1000 people 
Now setting up Test Hypothesis
Null 
Alternative 
The Test statistics is mathematically represented as
substituting values
