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Rom4ik [11]
3 years ago
9

The left and right page numbers of an open book are two consecutive integers whose sum is 557. Find these page numbers.

Mathematics
1 answer:
Alex Ar [27]3 years ago
5 0

Answer:

278+279=557

Step-by-step explanation:

hope this helps

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VERY EASY, WILL GIVE 50 POINTS FOR CORRECT ANSWER ASAP AND WILL GIVE BRAINLIEST.
timurjin [86]

Answer:

C

Step-by-step explanation:

3 0
3 years ago
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Hi again here's the picture
pshichka [43]

Answer:

<h2>351.88 m</h2>

Step-by-step explanation:

Given,

D = diameter of semicircular part = 42 m

L = Length of straight part = 110 m

Now, let's find the perimeter:

= 2 ( length of semi-circle + length of straight part )

= 2( \frac{\pi \: d}{2}  + l)

Plug the values

= 2( \frac{3.14  \times 42}{2}  + 110)

Calculate the product

= 2( \frac{131.88}{2}  + 110)

Divide

= 2 (65.94 + 110)

Calculate the sum

= 2 \times 175.94

Calculate

= 351.88 \: m

Hope this helps..

Best regards!!

8 0
3 years ago
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List from smallest to largest 7/12 1/2 2/3 4/10 1/6​
Vlad1618 [11]

Answer:

So if you're having difficulty visualizing the differences, you can rewrite them so they all have the same denominator

7/12 = 35/60

1/2 = 30/60

2/3 = 40/60

4/10 = 24/60

1/6 = 10/60

So now it's easier to see how they compare to each other.

10/60, 24/60, 30/60, 35/60, 40/60

And then simplify them or just refer to what they were before

1/6, 4/10, 1/2, 7/12, 2/3

I hope this helps!

3 0
3 years ago
Points D, E, and F are on circle C and EF ≅ DF. What is the measure of ∠CDF?
antiseptic1488 [7]
The answer is 

26 degrees 

I just did the test hope this helps :)
6 0
3 years ago
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For what value of c is the function defined below continuous on (-\infty,\infty)?
kozerog [31]
f(x)= \left \{ {{x^2-c^2,x \ \textless \  4} \atop {cx+20},x \geq 4} \right&#10;

It's clear that for x not equal to 4 this function is continuous. So the only question is what happens at 4.
<span>A function, f, is continuous at x = 4 if 
</span><span>\lim_{x \rightarrow 4} \  f(x) = f(4)

</span><span>In notation we write respectively
</span>\lim_{x \rightarrow 4-} f(x) \ \ \ \text{ and } \ \ \ \lim_{x \rightarrow 4+} f(x)

Now the second of these is easy, because for x > 4, f(x) = cx + 20. Hence limit as x --> 4+ (i.e., from above, from the right) of f(x) is just <span>4c + 20.
</span>
On the other hand, for x < 4, f(x) = x^2 - c^2. Hence 
\lim_{x \rightarrow 4-} f(x) = \lim_{x \rightarrow 4-} (x^2 - c^2) = 16 - c^2

Thus these two limits, the one from above and below are equal if and only if
 4c + 20 = 16 - c²<span> 
 Or in other words, the limit as x --> 4 of f(x) exists if and only if
 4c + 20 = 16 - c</span>²

c^2+4c+4=0&#10;\\(c+2)^2=0&#10;\\c=-2

That is to say, if c = -2, f(x) is continuous at x = 4. 

Because f is continuous for all over values of x, it now follows that f is continuous for all real nubmers (-\infty, +\infty)

4 0
3 years ago
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