we know that
A figure before the transformation is called pre-image and the figure after a transformation is called image
therefore
<u>the answer is the option D</u>
Image
Answer:
for r= 70 cm
the rate is 0.008cm/s
for r=95cm
the rate= 0.0044cm/s
Step-by-step explanation:
kindly find attached a rough sketch of the circle and a detailed solution of the problem.
Given data
rate dv/dt=500cm^3
r=70cm
r=95cm
2√2
= 2√2
B)
√3(√2+380√2-80)
= -80√3+381√6
I hope that's help and sorry for the late answer !
The answer is D. The ones on the left are the domain. The ones on the right which the arrows point to are the range
Answer:
The three digit number = 951
Step-by-step explanation:
Let suppose the numbers are:
= abc
According to given condition:
a+ b + c = 15 -------------eq1
Also, given the difference between the first two digit = the difference between the last two digits:
==> l a-b l = l b-cl
==> (a-b) = (b-c)
==> (a+c) = 2b
Now we will substitue in eq1
==> a+ b + c = 15
==> 2b + b = 15
==> 3b = 15
Dividing both sides by 3 we get:
b =5
a + c = 2b
a+ c = 10
a = 10 -c ..........(2)
We know that"
(a-b) = (b-c)
==> a > b+c
==> a > 5 + c
==> 10 -c > 5 +c
==>5 > 2c
==> 2.5 > c
As c is an odd number so c will be equal to 1
c = 1
a = 10 -1
a = 9
The three digit number = 951
The hundred digit is greater than the sum of the tens and ones digits
i hope it will help you!
