Answer:
E(X) = 1.5
Var(X) = 2.325
Step-by-step explanation:
X - the number of pairs of cats (out of the 5 cats) to choose the same type of treat, can take values of:
X = (0, 1, 2, 3, 4, 5)
Also probability of choosing a treat, since they are all equally likely is: f(x) = 1/10
E(X) - expectation of x, is given by:
E(X) = Summation [X*f(x)]
E(X) = 0x(1/10) + 1x(1/10) + 2x(1/10) + 3x(1/10) + 4x(1/10) + 5x(1/10)
= (1/10) x (1+2+3+4+5)
E(X) = 3/2 = 1.5
Also, variance is:
Var(X) = Summation f(x)*[X - E(X)]^2
= (1/10)x(0-1.5)^2 + (1/10)x(1-1.5)^2 +(1/10)x(2-1.5)^2 +(1/10)x(3-1.5)^2 +(1/10)x(4-1.5)^2 +(1/10)x(5-1.5)^2
= (1/10)x[2.25 + 0.25 + 2.25 + 6.25 + 12.25]
Var(X) = 2.325
Answer:
so you know that a line is 180-degrees, and that 119-degree angle is a part of that line, so you would take 180-119=61. so angle M=61 degrees
Step-by-step explanation: doge
Answer:
the correct answer is -5x - 1
Step-by-step explanation:
so we can safely say that one train will be there for 3.5 minutes and it will be gone for 16 minutes before another train comes and repeats the cycle.
we want how many minutes that the train will not be there over the total time that is possible so that would be
16/(16+3.5)
16/19.5
32/39
Hope that helps :)