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DochEvi [55]
2 years ago
14

Consider the expression 6x6^0x6^-3

Mathematics
1 answer:
Montano1993 [528]2 years ago
6 0

Answer:

6*(6^-3)=0.027777 recurring

Step-by-step explanation:

6^0=1

6^-3=0.004629629 recuuring

0.004629629 recurring *6=0.0.02777recurring

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What is the length (magnitude) of the vector (5 -2) <br> a. √29<br> b. 5√5<br> c. 5<br> d.√2
malfutka [58]

Answer:

a. √29

Step-by-step explanation:

The formula for the magnitude of a vector is magnitude = sqrt(x^2 + y^2).

For vector (5, -2):

magnitude = sqrt(5^2 + -2^2)

magnitude = sqrt(25 + 4)

magnitude = sqrt(29)

Therefore, the answer is √29.

Hope this helped :D

8 0
3 years ago
Help plz I need to solve this ​
tankabanditka [31]

Answer:

2,5

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Please procedure and solution <br><br>2 x |-6|-3 x |2|+|-14|=​
lora16 [44]

Applying the rule of modulus for given values, the expression will result to 20.

<h3>What is Modulus or Absolute Values</h3>

The modulus of a value for example |a|=a if a is greater than or equal to zero

and also

|a|=-a if a is less than zero

In the expression given; the modulus of -6 written as

|-6|=-(-6) this is because the value is less than zero

The modulus of 2 written as; |2|=2 this is because the value is greater than zero. and;

|The modulus of -14 written as; |-14|= -(-14) since the value is less than zero.

Hence, we can rewrite the expression as;

we deal with multiplication first following the rules of BODMAS

2×-(-6)-3×2+[-(-14)]

2×6-6+14

and thus adding values

12+14-6

and finally we subtract;

26-6

which will results to the solution of 20.

5 0
2 years ago
What is the equation of the line that passes through point P (6, -8) and has a slope of zero?
EleoNora [17]

Answer:

A

Step-by-step explanation:

because it is a straight line locate at x = 6 that pass to every y coordinate, so it pass -8 too.

8 0
3 years ago
What is the y-intercept of the function y = –2(2)^x+ 2?
NISA [10]
Y=mx+b
so is 2
the last number of the equation
8 0
3 years ago
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