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Pavel [41]
2 years ago
10

Need some help please.

Mathematics
1 answer:
melomori [17]2 years ago
6 0

Applying the rules of exponents, the letter answers that form the code are: MATH IS NOT JUST ANOTHER FOUR LETTER WORD.

<h3>What are the Rules of Exponents?</h3>

Some of the rules of exponents to be applied are as follows:

x^0 = 1\\\\x^m \times x^n = x^{(m + n)}\\\\x^{-m} = \frac{1}{x^m} \\\\x^m \div x^n = x^{(m - n)}\\\\

<h3>What are Equivalent Expressions?</h3>

If two expressions have the same value, both are said to be equivalent expressions.

1. 3^2 \times 3^{-5} = 3^{2 - 5}\\\\

3^-3 = \frac{1}{3^3} = \frac{1}{27}

Answer: H

2. 3³/6² = 27/36 = 3/4

Answer: R

3. \frac{3^2}{3^5} = 3^{2 - 5} = 3^{-3]} = \frac{1}{3^3} = \frac{1}{27}

Answer: M

4. 7²/7² = 49/49 = 7° = 1

Answer: J

5. 8^-2 = 1/8² = 1/64

Answer: A

6. (4²)(4³) = 4^(2 + 3) = 4^5

Answer: L

7. (3²)³ = 3²*³ = 3^6

8. 4° × 4^-1 = 1 × 1/4 = 1/4

Answer: E

9. \frac{(2^4)^3}{(2^7)(2^5)} = \frac{2^{12}}{2^{12}} = 1

Answer: U

10. (3^2)^{-1} = 3^{-2}

Answer: I

11. 1^{98} = 1

Answer: D

12. y^{10} \div y^5 = y^{10 - 5} = y^5

Answer: F

13. 8^{-2} \times 8^4 = 8^{(-2 + 4)} = 8² = 64

Answer: S

14. 2^{-3} \times 3^{-2} = 1/2³ × 1/3² = 1/8 × 1/9 = 1/72

Answer: O

15. \frac{3^2}{3^2} = 3^{2-2} = 3^0 = 1

Answer: N

16. (\frac{1}{2} )^{-1} = (2^{-1})^{-1} = 2

Answer: T

Thus, applying the rules of exponents, the letter answers that form the code are: MATH IS NOT JUST ANOTHER FOUR LETTER WORD.

Learn more about the rules of exponents on:

brainly.com/question/12140519

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Answer:

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So then we have that Morten Andersen scored on average 97.45 points per year in his career.

Step-by-step explanation:

Assuming the following table on the figure attached.

We see that the career points for Morten Andersen was 2437. That include all the points over alll the years the he played in the NFL.

Since the total years played by Morten Andersen was 25 we can write the following equation:

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If we solve for r from the last equation we can divide both sides of the equation and we got:

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