All categories

3 years ago

On a loan of $1200 at 15% annual interest, Shirley had to pay $135 interest. For how many months did she have the loan?

Mathematics

2 answers:

DanielleElmas [232]3 years ago

4 0

Answer: 9 months .

natulia [17]3 years ago

3 0

Answer:

<u><em>9 months</em></u>

Step-by-step explanation:

Principal= P= $1200

Rate=R= 15%

Interest= I= $135

Time= T= ?

I=P*R*T/100

135= 1200*15*T/100

135*100=18000*T

13500/18000=T

T= 0.75 years

T= 0.75*12= 9 months

You might be interested in

PLZ GIMME A FRIEND REQUEST. IM LONELYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY

LekaFEV [45]

Answer:

Tamē kēvī rītē mitra vinantī ahīṁ mōkalī śakō chō

7 0

3 years ago

Read 2 more answers

Heights for women are bell-shaped with a mean of 65 inches and standard deviation of 2.5 inches. If a random sample of 16 women

loris [4]

Answer:

μ= 65 inches; σ= 0.625 inch

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed(bell-shaped) random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

$\mu = 65, \sigma = 2.5$

By the central limit theorem, the sample of 16 will have:

$\mu = 65, \sigma = \frac{2.5}{\sqrt{16}} = 0.625$

So the correct answer is:

μ= 65 inches; σ= 0.625 inch

8 0

3 years ago

Pls help no links in the answer

Dominik [7]

Answer:

Hello my friend, I hope this helps you!

Step-by-step explanation:

7 0

3 years ago

The vertex of this parabola is at (-3,2). Which of the following could be its equation?

VashaNatasha [74]

vertex form of a parabola

y= a(x-h)^2 +k

y =a(x--3)^2 +2

y = a(x+3)^2 +2

Choice B

7 0

3 years ago

Read 2 more answers

ln(y+1)-lny=1+3lnx . Express y in terms of x, in a form not involving logarithms. (4 marks, Maths CIE A level)

Delicious77 [7]

$remember$
$ln(x)=log_e(x)$
$and$
$log_x(a)-log_x(b)= log_x( \frac{a}{b} )$
$and$
$log_a(b)=c$ means $a^c=b$
$and$
$blog(a)=log(a^b)$

$so$

$ln(y+1)-ln(y)=1+3ln(x)$
$ln( \frac{y+1}{y} )=1+ln(x^3)$

$minus$ $ln(x^3)$ $from$ $both$ $sides$

$ln( \frac{y+1}{y}-ln(x^3) )=1$
$ln( \frac{y+1}{yx^3})=1$
$log_e( \frac{y+1}{yx^3})=1$

$translate$

$e^1=\frac{y+1}{yx^3}$
$e=\frac{y+1}{yx^3}$

$times$ $both$ $sides$ $by$ $yx^3$

$eyx^3=y+1$

$minus$ $y$ $from$ $both$ $sides$

$eyx^3-y=1$
$y(ex^3-1)=1$

$divide$ $both$ $sides$ $by$ $(ex³-1)$

$y= \frac{1}{ex^3-1}$

6 0

3 years ago

Read 2 more answers