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2 years ago

13

Can someone hepl me solve this it is importaint thank you so much ? 4/7x5/3x3/4=?

1 answer:

erastovalidia [21]2 years ago

3 0

Answer:

5/7 is the answers for the question

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What is a word problem for<br><br> 5x + 10 ≥ 50

aliya0001 [1]

solve for x by simplifying both sides of the equation,then isolating the variable x>8

7 0

3 years ago

Given that f(x) = 6x - 5 g(x) = 3x + 4 and h(x) = 4x – 6

bazaltina [42]

Answer:

(i) $g(-2)=-2$

(ii) $g[h(x)]=12x-14$

(iii) $f[g(2)]=55$

(iv) $(g\circ h)(2)=10$

(v) $h^{-1}(11)=\frac{17}{4}$

Step-by-step explanation:

The given functions are

$f(x)=6x-5$

$g(x)=3x+4$

$h(x)=4x-6$

(i) Find g(-2).

Substitute x=-2 in g(x).

$g(-2)=3(-2)+4\Rightarrow -6+4=-2$

(ii) Find g[h(x)]

$g[h(x)]=g(4x-6)$ $(h(x)=4x-6)$

$g[h(x)]=3(4x-6)+4$ $(g(x)=3x+4)$

$g[h(x)]=12x-18+4$

$g[h(x)]=12x-14$

(iii) Find f[g(2)].

$f[g(2)]=f[3(2)+4]$ $(g(x)=3x+4)$

$f[g(2)]=f(6+4)$

$f[g(2)]=f(10)$

$f[g(2)]=6(10)-5$ $f(x)=6x-5$

$f[g(2)]=55$

iv) Find gᴏh(2).

$(g\circ h)(2)=g[h(2)]$

$(g\circ h)(2)=12(2)-14$ (From part (ii) we get $g[h(x)]=12x-14)$

$(g\circ h)(2)=10$

(v) Find $h^{-1}(11)$

First find $h^{-1}(x)$ .

$h(x)=4x-6$

$y=4x-6$

$x=4y-6$

$x+6=4y$

Divide both sides by 4.

$\frac{x+6}{4}=y$

$h^{-1}(x)=\frac{x+6}{4}$

Substitute x=11 in the inverse function.

$h^{-1}(11)=\frac{11+6}{4}$

$h^{-1}(11)=\frac{17}{4}$

6 0

4 years ago

What value of c in the equation + 4 = 12 would give the equation a slope of 8? (show your work)

Vanyuwa [196]

3 4×3=12 yeah I'm pretty sure this is right

3 0

3 years ago

What is the slope of the line represented by the equation y =<br> -1/2x+1/4?

Dmitry_Shevchenko [17]

Answer:

-1/2

negative

Step-by-step explanation:

7 0

3 years ago

Question is in the image

nika2105 [10]

It is b i think hope this helps

8 0

3 years ago