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3 years ago

5

What is 5(-3k+5)=-4K+k+1

1 answer:

enot [183]3 years ago

6 0

Answer:

Step-by-step explanation:

5(-3k+5)=-4K+k+1

Opening bracket

-15k + 25 = -4k + k + 1

-15k + 4k - k = 1 - 25

-12k = -24

k = -24/-12

k = 2

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The owner of an auto repair shop studied the waiting times for customers who arrive at the shop for an oil change. The following

labwork [276]

Answer:

(d)0.6

Step-by-step explanation:

(a)Frequency Distribution

$\left|\begin{array}{c|c}$Waiting Time(in Minutes)&$Frequency\\-----------&--\\0-4&4\\5-9&8\\10-14&5\\15-19&2\\20-24&1\\--&--\\Total&20\end{array}\right|$

(b)The relative frequency distribution.

$\left|\begin{array}{c|c}$Waiting Time(in Minutes)&$Relative Frequency\\-----------&--\\0-4&4/20=0.2\\5-9&8/20=0.4\\10-14&5/20=0.25\\15-19&2/20=0.1\\20-24&1/20=0.05\\--&--\\Total&1\end{array}\right|$

(c)The cumulative frequency distribution.

$\left|\begin{array}{c|c|c}$Waiting Time(in Minutes)&$Frequency&$Cumulative Frequency\\-----------&--&---\\0-4&4&4\\5-9&8&12\\10-14&5&17\\15-19&2&19\\20-24&1&20\\--&--&--\\Total&20\end{array}\right|$

(d)The proportion of customers needing an oil change who wait 9 minutes or less.

Proportion of customers needing an oil change who wait 9 minutes or less.

$=\dfrac{12}{20} \\\\=0.6$

5 0

3 years ago

Please help<br> See the picture <br> Twst

erik [133]

Answer:

7

Step-by-step explanation:

1. Use sine law to solve

3/sin35 = x/sin55

3sin55/sin35 = 7

6 0

3 years ago

Can someone give me the answers I don't get this at all

Vikentia [17]

5 to 8 right or there more

4 0

3 years ago

Read 2 more answers

Please help with these two questions and give an accurate answer. I will mark u the brainiest. Sinking Rivers charges two hundre

Soloha48 [4]

Answer:

Step-by-step explanation:

First one is 200 dollars for insurance which will be the constant and 15 dollars an hour which means the equation will be;

C = 15h +200 (Sinking Rivers)

Second one is $30 an hour and $110 for insurance which is the constant so he equation is;

C = 30h + 110 (Floating Down The Stream)

5 0

3 years ago

Prove that sin^4x + cos^4x= sinxcosx

yKpoI14uk [10]

Answer:

(the relation you wrote is not correct, there may be something missing, so I will simplify the initial expression)

Here we have the equation:

$sin^4(x) + cos^4(x)$

We can rewrite this as:

$(sin^2(x))^2 + (cos^2(x))^2$

Now we can add and subtract cos^2(x)*sin^2(x) to get:

$(sin^2(x))^2 + (cos^2(x))^2 + 2*cos^2(x)*sin^2(x) - 2*cos^2(x)*sin^2(x)$

We can complete squares to get:

$(cos^2(x) + sin^2(x))^2 - 2*cos(x)^2*sin(x)^2$

and we know that:

cos^2(x) + sin^2(x) = 1

then:

$1 - 2*sin(x)^2*cos(x)^2$

This is the closest expression to what you wrote.

We also know that:

sin(x)*cos(x) = (1/2)*sin(2*x)

If we replace that, we get:

$1 - \frac{sin^2(2*x)}{2}$

Then the simplification is:

$cos^4(x) + sin^4(x) = 1 - \frac{sin^2(2*x)}{2}$

7 0

3 years ago