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DIA [1.3K]
3 years ago
15

Question 6 of 25

Mathematics
1 answer:
Roman55 [17]3 years ago
7 0

Answer:

2/3

Step-by-step explanation:

Add all the number of marbles.Now you have 15 in total. 10 of them are not yellow. 10/15 simplified equals 2/3

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PLEASE HELP ME!!!
slamgirl [31]

Answer:

Step-by-step explanation:

7 0
3 years ago
HELP PLEASE !! NEED HELP ASAPPP !! Will give brainliest !!!
Katyanochek1 [597]

Answer:

Measure of angle DBF = 106°.

Step-by-step explanation:

Given in the question,

m∠DGE = 53°

and line segment GE is the angle bisector of ∠DGF.

Since segment GE is the angle bisector of ∠DGF that means it divides the angle DGF into two equal parts.

Therefore, m∠DGE ≅ m∠FGE

m∠DBF = m∠DGE + m∠FGE

m∠DBF = 2(m∠DGE)

             = 2(53)°

             = 106°

Therefore, measure of angle DBF = 106°.

8 0
3 years ago
This is my math geometry... What does x equal on the shape to the right?
andrezito [222]

Answer:

x=12

Step-by-step explanation:

It is a textbook 3:4:5 triangle. The hypotenuse is 15 (5*3), and the base is 9 (3*3). Since they both share a common factor of 3, the 3rd side would be 4*3, which is 12.

5 0
3 years ago
draw the image of figure after each translation number 9. four units left and 4 unit down number 10 five units right in three un
Alex787 [66]

The coordinates for the pre-image are P(1,3), Q(4,4), R(4,1), and S(1, -1).

The transformation is 4 units left, and 4 units down.

That means we must subtract 4 units to x-coordinates, and subtract 4 units from y-coordinates. So, the image has coordinates P'(-3,-1), Q'(0,0), R'(0, -3), and S'(-3, -5).

The image below shows the image and pre-image.

5 0
1 year ago
The diagram shows a 9cm x 7cm rectangle-based pyramid. all the diagonal sides - TA, TB, TC, AND TD- are length 12cm. M is the mi
lakkis [162]

Answer:

∠TAC is approximately equal to 61.6°

Step-by-step explanation:

The given parameters for the pyramid are;

The dimension for the rectangular base are; Length = 9 cm, width = 7 cm

The length of the diagonal sides, TA, TB, TC, and TD = 12 cm each

The midpoint of the rectangular base = Point M

The diagonal AC = AM + MC

AM = MC as given M is the midpoint of the rectangular base

∴ AC = AM + MC = 2·AM

By Pythagoras' theorem, AC = √(9² + 7²) = √130

AC = √130 cm

∴ AM = AC/2 = (√130)/2 cm

Alternatively, AM = √((9/2 cm)² + (7/2 cm)²) = √(32.5) cm

∠TAC = ∠TAM

By trigonometric ratios, we have;

cos (\theta) = \dfrac{Length \ of \ adjacent \ side \ to \ angle }{Length \ of \ hypotenuse\ side \ to \ angle}

\therefore cos (\angle TAM) = cos (\angle TAC) =  \dfrac{\left (\dfrac{\sqrt{130} }{2}   \right )}{12} = \dfrac{\sqrt{130} }{2 \times 12} = \dfrac{\sqrt{130} }{24}

\angle TAC = arccos \left ( \dfrac{\sqrt{130} }{24} \right ) \approx  61.6 ^{\circ} \ to 1 \ decimal \ place

6 0
3 years ago
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