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Karo-lina-s [1.5K]
3 years ago
10

Factor the trinomial below.

Mathematics
1 answer:
ivann1987 [24]3 years ago
6 0
Answer: Choice C. (x-7)(x-8)

-------------------------------------------------------

Find two numbers that...
* Multiply to 56 (last term)
* Add to -15 (middle coefficient)

Those two numbers are -7 and -8. So that's why x^2-15x+56 factors to (x-7)(x-8)
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How many 1/3 cup servings of juice are in a 5 cup container
vesna_86 [32]

Answer:

We can get 15  (1/3 cup) servings with a 5 cup container

Step-by-step explanation:

To solve this problem, we can easily divide 5 by (1/3)  to find how many servings can be obtained

5 /  (1/3)  

=  5 / (0.3333)

= 15

This can be checked by adding together (1/3) fifteen times

(1/3) + (1/3)+ (1/3)+ (1/3)+ (1/3)+ (1/3)+ (1/3)+ (1/3)+ (1/3)+ (1/3)+ (1/3)+ (1/3)+ (1/3)+ (1/3)+ (1/3)

= 15/3  = 5

7 0
3 years ago
Please Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
melamori03 [73]

Answer:

A-21 degrees more

B& degrees Fahrenheit

Step-by-step explanation:

8 0
3 years ago
Given below are lease terms at the local dealership. What is the total
Rus_ich [418]

Answer: 112.50

Step-by-step explanation:

4 0
3 years ago
The base and height of a right triangle are 20 inches and 15 inches. Find the length of the hypotenuse.
Karolina [17]

Using the Pythagorean theorem:

Hypotenuse = sqrt( 20^2 + 15^2)

Hypotenuse = sqrt( 400 + 225)

Hypotenuse = sqrt(625)

Hypotenuse = 25

Answer: 25 inches

8 0
3 years ago
Read 2 more answers
F(t)=t^2+19t+60<br> What are the zeros of the function and what is the vertex of the parabola?
SVEN [57.7K]

Answer: -4,-15;\ \left(-\dfrac{19}{2},-\dfrac{121}{4}\right)

Step-by-step explanation:

Given

Function is F(t)=t^2+19+60

Zeroes of the function are

t^2+19t+60=0\\\\\Rightarrow t=\dfrac{-19\pm\sqrt{19^2-4\times 1\times 60}}{2\times 1}\\\\\Rightarrow t=\dfrac{-19\pm \sqrt{121}}{2}\\\\\Rightarrow t=\dfrac{-19\pm 11}{2}\\\\\Rightarrow t=-4,-15

Using completing the square method

y=t^2+2\times \dfrac{19}{2}t+\dfrac{19^2}{2^2}-\dfrac{19^2}{2^2}+60\\\\y=\left(t+\dfrac{19}{2}\right)^2+60-\dfrac{361}{4}\\\\y=\left(t+\dfrac{19}{2}\right)^2-\dfrac{121}{4}\\\\y+\dfrac{121}{4}=\left(t+\dfrac{19}{2}\right)^2\\\\\left(y-(-\dfrac{121}{4}\right)=\left(t-(-\dfrac{19}{2})\right)^2\\\\\text{The vertex is }\left(-\dfrac{19}{2},-\dfrac{121}{4}\right)

4 0
3 years ago
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