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Fiesta28 [93]
3 years ago
9

Beau spun a tri-colored spinner 30 times. The spinner stopped 12 times on yellow, 5 times on red, and 13 times on blue. Based on

this data, if Beau spins the spinner 420 times, how many times would the spinner be expected to stop on red?
Mathematics
1 answer:
s2008m [1.1K]3 years ago
4 0

Answer:70

Step-by-step explanation:30 divided by 6 equals 5. And 420 divided by 6 equals 70

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Calculate the area.<br><br> please help!
VikaD [51]

Answer:

459

Step-by-step explanation:

first we solve the area of the rectangle. the length of the rectangle is 22 and the width is 18. 22 times 18=396. next we need to solve the area of the triangle. 7 is the height of the triangle and 18 is the width. 7 times 18 divided by 2 is 63. Next we need to add up the area of the rectangle and the triangle

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Use the substitution method to solve the system of equations 8x5y=9 y=x+7
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Answer:

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Step-by-step explanation:

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The running trail in the local park is 2.826 miles long. If the park board were planning to extend the trail by 1.46 miles, what
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4 years ago
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3 0
4 years ago
Assume that military aircraft use ejection seats designed for men weighing between 141.8 lb and 218 lb. If​ women's weights are
Mariulka [41]

Answer:

P(141.8

And we can find this probability with this difference and using the normal standard table:

P(-0.639

Then the answer would be approximately 55.3% of women between the specifications. And that represent more than the half of women

Step-by-step explanation:

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(173.6,49.8)  

Where \mu=173.6 and \sigma=49.8

We are interested on this probability

P(141.8

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(141.8

And we can find this probability with this difference and using the normal standard table:

P(-0.639

Then the answer would be approximately 55.3% of women between the specifications. And that represent more than the half of women

8 0
3 years ago
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