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algol [13]
2 years ago
7

In FGH,FH =7 ft,FG=12 ft and m

Mathematics
1 answer:
nikdorinn [45]2 years ago
5 0

Answer:1) In Δ FGH,

FH=7 ft, FG=12 ft,

∠F=70 degrees

By "Law of cosines":

So,By applying Law of Sines , we get that

Hence, Option 'D' is correct.

2) In Δ XYZ,

XY=14, ∠Y=22°, and XZ=26

By using "Law of sines":

so, X = 147° , Y = 22° , Z = 11.6°

Step-by-step explanation:

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Share £480 in the ratio 2:3:7
aleksandr82 [10.1K]
£480

2:3:7 =  2+3+7  = 12

 2
--- 0f £480 = £80
12


 3
--- of £480 = £120
12

 7
--- of £480 = £280
12


answer =  £80 : £120 : £280
5 0
4 years ago
I NEED HELP PLEASE WITH PART 2, THANKS!
EleoNora [17]

Steps to solve:

-6w - 8 + 15w = 2w - 8 + 7w

~Combine like terms

9w - 8 = 9w - 8

~Add 8 to both sides

9w = 9w

~Divide 9 to both sides

0 = 0

All real numbers are solutions.

Set builder notation: {x | R}

Best of Luck!

8 0
3 years ago
if the volume of the pyramid is 81 in cubed, and l equals w equals 3 h, what is the length of the base of the pyramid in inches?
ikadub [295]

The length of the base of the pyramid is 9 inches

<em><u>Solution:</u></em>

<em><u>The volume of pyramid is given by formula:</u></em>

volume = \frac{l \times w \times h}{3}

Where, "l" is the length and "w" is the width and "h" is the height

Given that,

volume of pyramid = 81 cubic inches

Also given that, l equals w equals 3 h

<h3>l = w = 3h </h3>

Substitute the values in formula,

81 = \frac{3h \times 3h \times h}{3}\\\\81 = 3h^3\\\\h^3 = 27\\\\\text{Take cube root on both sides }\\\\h = \sqrt[3]{27} \\\\h = \sqrt[3]{3 \times 3 \times 3} = \sqrt[3]{3^3} \\\\h = 3

Thus height = 3 inches

We have to find the length

l = 3h

l = 3(3) = 9

Thus length of the base of the pyramid is 9 inches

7 0
4 years ago
867 m as a fraction ....
lesantik [10]

Answer:

867000 / 1000

Step-by-step explanation:

To express in the form of a fraction :

An expression could be said to be in fraction form, if written in the form ; a/b ; where a = numerator and b = denominator

Hence the number :

867 m could be expressed as a fraction :

867 / 1 where 867 = numerator ; 1 = denominator

Or

867000 / 1000 ; 867000 = numerator ; 1000 = denominator

3 0
3 years ago
Excluded values for y=5/(6x-72)<br> (the / is a fraction so its 5 over 6x)
lapo4ka [179]
The denominator cannot equal zero. Set the expression on the denominator = to zero to find the value that must be excluded.
6x - 72 = 0
add 72 to both sides
6x = 72
Divide both sides by 6
x = 9
The excluded value is 9.
5 0
3 years ago
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