Answer:
No. Steven is not correct.
Step-by-step explanation:
The area of shape A is 15 (either multiply 5 x 3 or just count squares). The area of shape B is 9.
15 is not double 9.
5 + (-1) is the same thing as 5-1
So it's 4.
Given A={1,2,3}, B={2,4,6} and C={1,2,3,4,5,6}, then A ∩ (B ∩ C) =
oksian1 [2.3K]
Answer:
Step-by-step explanation:
A={1,2,3}
B={2,4,6}
C={1,2,3,4,5,6}
B∩C={2,4,6}
A∩(B∩C)={1,2,3}∩{2,4,6}={2}
x=8 is the answer fellow user
(x - 1)(x - 2)(x + 2)
note that the sum of the coefficients 1 - 1 - 4 + 4 = 0
thus x = 1 is a root and (x - 1 ) is a factor
dividing x³ - x² - 4x + 4 by (x - 1)
x³ - x² - 4x + 4 = (x - 1)(x² - 4 ) (note (x² - 4 ) is a difference of squares )
x³ - x² - 4x + 4 = (x - 1)(x - 2)(x + 2)
(x - 1)(x - 2)(x + 2 ) =0
x - 1 = 0 ⇒ x = 1
x - 2 = 0 ⇒ x = 2
x + 2 = 0 ⇒ x = - 2
solutions are x = 1 or x = ± 2
