Answer:
Option a) A 95% confidence interval for the mean diameter of the 120 bearings in the sample is
.
Step-by-step explanation:
We are given the following information in the question:
Sample size, n = 120
Sample mean = 10 mm
Standard Deviation = 0.24 mm
Formula:
![\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=%5Cmu%20%5Cpm%20z_%7Bcritical%7D%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
![z_{critical}\text{ at}~\alpha_{0.05} = 1.96](https://tex.z-dn.net/?f=z_%7Bcritical%7D%5Ctext%7B%20at%7D~%5Calpha_%7B0.05%7D%20%3D%201.96)
![10 \pm 1.96\displaystyle\frac{0.24}{\sqrt{120}}](https://tex.z-dn.net/?f=10%20%5Cpm%201.96%5Cdisplaystyle%5Cfrac%7B0.24%7D%7B%5Csqrt%7B120%7D%7D)
Hence, the correct interpretation for the confidence interval is given by option a).
A 95% confidence interval for the mean diameter of the 120 bearings in the sample is
.
We have to consider the factor of sampling of 120 ball bearings from a population of 10,000 ball bearings.
The answer is 3x+4y-7=0. The line will have a negative slope.
Answer:
Equality
Step-by-step explanation:
x = 6
7x = 42
7 * 6 = 42
42 = 42
I think it is 16 because I just divided it, I’m sorry if you will get it wrong I’m not sure
4842 / 93 = 52.064516129
i would reccomend you round it to:
52.06
i hope this helped have a nice day and plz vote me for brainliest! :)