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ss7ja [257]
4 years ago
7

Negative 4 over 5 plus fours times one over three

Mathematics
1 answer:
borishaifa [10]4 years ago
7 0

Answer:

0.53333333333

Step-by-step explanation:

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Giving BRAINLIEST to the CORRECT answer.
olga nikolaevna [1]

Answer:a

Step-by-step explanation:

it became wider by decreasing two on the graph.

7 0
3 years ago
Monty buys hats in bulk to sell at his store. His cost for each hate is $17. He marks up the hats 45%. What is the retail price
maksim [4K]

Answer:

i believe it is 7.65, i am not 100% sure though..

Step-by-step explanation:

8 0
3 years ago
HOW do you find the value of TAN 88 degrees 22' 45'' and COT 36 degrees???
storchak [24]
Part 1
We want to find the tan of 88 degrees, 22' 45''.

88° 22' 45''
= 88 + 22/60 + 45/3600 degrees
= 88.3792°

From the calculator, obtain
tan(88.3792°) = 35.3409

Answer: 35.3409

Part 2
We want to find cot(36°).

By definition, cot(x) = 1/tan(x).
From the calculator, obtain
tan(36°) = 0.7265
Therefore
cot(36°) = 1/0.7265 = 1.3764

Answer: 1.3764

3 0
4 years ago
What are the closest two intergers that √300 is between?
jeka57 [31]
\sqrt{a}=b\iff b^2=a\\\\17 < \sqrt{300} < 18\ because\\\\17^2=289 < 300\ and\ 18^2=324 > 300
3 0
4 years ago
You are handed two envelopes, and you know that one of each contains a positive integer dollar amount and that the two amounts a
satela [25.4K]

Answer:

I suppose maybe the catch is in interpreting the following sentence: "The values of these two amounts are modeled as constants that are unknown". I take it to mean that they're just two randomly and independently generated numbers.

Step-by-step explanation:

The answer given in the solution manual claims that this indeed helps, and that the probability of getting the better envelope is given by

p=1/2+1/2P(B)

where B is the event that a<X<b, with a,b being the smaller and larger amount of dollars, respectively.

I do not buy this solution for the following reason: tossing a coin has nothing to do with the contents of the envelopes. You do not gain any information by doing it. You could just as well count the amount of leaves on a nearby tree instead and use that for X.

Similarly, opening the first envelope also gives you no useful information about the ordering relation between a and b, so surely that's another red herring. Even if you forget the coin tossing, the probability of "winning" is still 1/2, swap or no swap.

8 0
3 years ago
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