So we have
120x2y5 and 80x3y2
120 doesnt divide into 80 evenly, but we know 40 goes into both.
so the first part is 80x
2y and 3y dont have a common factor other than y so the second part is
y
2 and 5 dont share any common factors so we simply leave that alone
so we have 40xy
Answer:
TOOOO MUCH LIKE GOD D.A.MN
Step-by-step explanation:
Answer:
529 cm²
Step-by-step explanation:
Area of the square
= 23 ×23
= 529 cm²
Answer:
Step-by-step explanation:
The null hypothesis and alternative hypothesis can be formulated as:
From the information given:
The sample proportion of rooms occupied for the current year.
Sample size = 1750 (total number of rooms for the current year)
The sample proportion of rooms occupied for the previous year.
Sample size = 1800 (total number of rooms for the previous year)
Thus, the estimated proportion of the hotel rooms occupied each year are:
Current Previous
0.84 0.80
Since this is a one-sided right-tailed test;
The pooled proportion can be computed as:
The standard error SE =
Finally, the test statistics is calculated as:
<h3><u>Correct </u><u>Question </u><u>:</u><u>-</u></h3>
What is the 5th term of an AP 2 , 14 ....98 .
<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>
<u>We </u><u>have </u><u> </u><u>AP</u><u>, </u>
- <u>AP </u><u>is </u><u>the </u><u>arithmetic </u><u>progression </u><u>or </u><u>a </u><u>sequence </u><u>of </u><u>numbers </u><u>in </u><u>which </u><u>succeeding </u><u>number </u><u>is </u><u>differ </u><u>from </u><u>preceeding </u><u>number </u><u>by </u><u>a </u><u>common </u><u>value</u><u>. </u>
<h3><u>Solution </u><u>:</u><u>-</u></h3>
<u>We </u><u>have </u><u>an </u><u>AP </u><u>:</u><u>-</u><u> </u><u>2</u><u> </u><u>,</u><u> </u><u>1</u><u>4</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>9</u><u>8</u>
<u>Therefore</u><u>, </u>
<u>Here</u><u>, </u>
Common difference of an AP
Thus, The common difference is 12
<u>Now</u><u>, </u>
We know that,
Hence, The 5th term of given AP is 50