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2 years ago

Traingle Congruence, FlowChart Proof Level2, 10th Grade

Mathematics

1 answer:

Mariulka [41]2 years ago

8 0

Answer:

Step-by-step explanation:

→1.

Statement : AB ≅AD (side)

Reason: Given

→2.

Statement : ∡BAC≅∡CAD (angle)

Reason: Given

→3.

Statement : AC ≅AC (side)

Reason: Reflexive Property -a side is congruent with itself

→

Statement : ΔABC ≅ΔADC

Reason: Side-Angle-Side Theorem of Congruency

(If two corresponding sides of two triangles are congruent and the corresponding angles between those two sides are congruent then the two triangles are congruent)

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Solve the system by substitution.<br> y= 2x2 – 3x-1<br> Y=x-3

mr Goodwill [35]

Answer:

x=0 or no solution?

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Step-by-step explanation:

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3 years ago

The difference of two number is 28. if one number is 11, find the other number

Leno4ka [110]

Answer:

Step-by-step explanation:

difference=28

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2 years ago

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A building casts a shadow 168 meters long. At the same time, a pole 5 meters high casts a shadow 20 meters long . What is the he

yawa3891 [41]

Answer:

Step-by-step explanation:

The height of the pole is 4 times shorter than the length of the shadow 20÷5=4

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3 years ago

Given the equation 5x − 4 = –2(3x + 2), solve for the variable. Explain each step and justify your process.

blagie [28]

A.
$5x-4=-2(3x+2) \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
5x-4=-2 \times 3x-2 \times 2 \\
5x-4=-6x-4 \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 6x to both sides} \\
11x-4=-4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 4 to both sides} \\
11x=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{divide both sides by 11} \\
x=0$

B.
$3(2x-4)=5x-1 \\
6x-12=5x-1 \\
\boxed{11x-12=-1} \Leftarrow \hbox{the first mistake} \\
11x=11 \\
\boxed{x=11} \Leftarrow \hbox{the second mistake}$

Megan's solution isn't correct.
The first mistake: she subtracted 5x from the right-hand side of the equation, but added 5x to the left-hand side.
The second mistake: she divided the right-hand side of the equation by 11, but didn't divide the left-hand side.

The correct solution:
$3(2x-4)=5x-1 \ \ \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
3 \times 2x+3 \times (-4)=5x-1 \\ 6x-12=5x-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{subtract 5x from both sides} \\
x-12=-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 12 to both sides} \\
x=11$

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2 years ago

I need help with this

Ad libitum [116K]

It’s 60 degrees so the first one

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2 years ago

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Traingle Congruence, FlowChart Proof Level2, 10th Grade​

Traingle Congruence, FlowChart Proof Level2, 10th Grade