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irina1246 [14]
2 years ago
5

To prove that the triangles are similar by the SAS similarity theorem, it needs to be shown that

Mathematics
1 answer:
MakcuM [25]1 year ago
6 0

Answer:

2 sides and angle between them are congruent to the same 2 sides and angle on the other triangle

Step-by-step explanation:

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What is the gradient of a line with an equation of 3x-2y-6=0​
Genrish500 [490]

Answer:

Slope <em>m</em> = 3/2

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Equality Properties

<u>Algebra I</u>

Slope-Intercept Form: y = mx + b

  • m - slope
  • b - y-intercept

Step-by-step explanation:

<u>Step 1: Define Equation</u>

3x - 2y - 6 = 0

<u>Step 2: Rewrite</u>

<em>Find slope-intercept form</em>

  1. Subtract 3x on both sides:                    -2y - 6 = -3x
  2. Add 6 on both sides:                             -2y = -3x + 6
  3. Divide -2 on both sides:                         y = 3/2x - 3

<u>Step 3: Break Function</u>

<em>Identify Parts.</em>

Slope <em>m</em> = 3/2

y-intercept <em>b</em> = -3

6 0
3 years ago
Can anyone help with this. Will give you all my points and brainliest:)
Nana76 [90]

Answer:3. 4:8

4. 1:4

Step-by-step explanation:

5. 48

6. 3

4 0
3 years ago
A data set consists of the following data points:
aleksley [76]
<span>(3,5),
(5,8),
(6,13)
------
(14,26)/3
 
then use the point slope form of a line to find equation of line

</span>y-y_1=m(x-x_1)&#10;\\y -  \frac{26}{3}  = 2.5(x- \frac{14}{3})&#10;\\y -  \frac{26}{3}  =  \frac{5}{2} (x- \frac{14}{3})&#10;\\y -  \frac{26}{3}  =  \frac{5}{2} x-  \frac{5}{2}\times\frac{14}{3}&#10;\\y -  \frac{26}{3}  =  \frac{5}{2} x-  \frac{35}{3}&#10;\\6y-52=15x-70&#10;\\15x-6y-18=0
<span>
Find y-intercept for x = 0.

</span>15x-6y-18=0&#10;\\15\times0-6y-18=0&#10;\\-6y=18&#10;\\y=-3<span>

</span>
4 0
3 years ago
The mean MCAT score 29.5. Suppose that the Kaplan tutoring company obtains a sample of 40 students with a mean MCAT score of 32.
Paul [167]

Answer:

We conclude that the students that took the Kaplan tutoring have a mean score greater than 29.5.

Step-by-step explanation:

We are given that the Kaplan tutoring company obtains a sample of 40 students with a mean MCAT score of 32.2 with a standard deviation of 4.2.

Let \mu = <u><em>population mean score</em></u>

So, Null Hypothesis, H_0 : \mu \leq 29.5      {means that the students that took the Kaplan tutoring have a mean score less than or equal to 29.5}

Alternate Hypothesis, H_A : \mu > 29.5      {means that the students that took the Kaplan tutoring have a mean score greater than 29.5}

The test statistics that will be used here is <u>One-sample t-test statistics</u> because we don't know about population standard deviation;

                               T.S.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean MCAT score = 32.2

            s = sample standard deviation = 4.2

            n = sample of students = 40

So, <u><em>the test statistics</em></u> =  \frac{32.2-29.5}{\frac{4.2}{\sqrt{40} } }  ~  t_3_9

                                    =  4.066

The value of t-test statistics is 4.066.

Now, at 0.05 level of significance, the t table gives a critical value of 1.685 at 39 degrees of freedom for the right-tailed test.

Since the value of our test statistics is more than the critical value of t as 4.066 > 1.685, so <u><em>we have sufficient evidence to reject our null hypothesis</em></u> as it will fall in the rejection region.

Therefore, we conclude that the students that took the Kaplan tutoring have a mean score greater than 29.5.

3 0
3 years ago
Help Me Please!!!!!!!!!!!!!!
vovikov84 [41]
First one is 5/15 next one is 5/5 next one is 15/3 next one is 15/5 I think u know how to simplify so ya
7 0
3 years ago
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