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kozerog [31]
3 years ago
10

Press the ____ key(s) to erase one character to the left of the insertion point.

Computers and Technology
2 answers:
Artist 52 [7]3 years ago
7 0
By pressing the 'DELETE' key with your cursor, you can erase a single character to the left of the insertion point. By pressing 'INSERT', then you would be able to replace characters to the left or right, whether you are deleting or adding a new character.
For more information, please follow the below links for reference:
http://www.schools.nsw.edu.au/learning/k-6assessments/csa6ictskills.php
erik [133]3 years ago
5 0
<span>To erase one character to the left of the insertion point i</span>t is the DELETE key.
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Consider a company that needs to sort an array of structures of type Customer by balance, with the largest balance first. Here i
8090 [49]

Answer:

#include <iostream>

#include <string>

#include <cstring>

#include <cstdlib>

using namespace std;

struct Person

{

string name;

int age;

};

int main()

{

struct Person data[10];

struct Person *pData[10],*temp;

string names[] = {"a","b","c","g","z","l","p","q","r","w"};

int num[] = {4,6,34,8,13,90,33,22,18,23};

for(int i=0;i<9;i++)

{

data[i].name = names[i];

data[i].age = num[i];

pData[i] = &data[i];

}

for(int i=0;i<9;i++)

{

for(int j=i+1;j<9;j++)

{

if(pData[i]->name.compare(pData[j]->name)>0)

{

temp = pData[i];

pData[i] = pData[j];

pData[j] = temp;

}

}

}

for(int i=0;i<9;i++)

{

cout<<pData[i]->name<<" "<<pData[i]->age<<endl;

}

}

Explanation:

The line #include <iostream> initializes the program.

This program created an array of only 10 structures, Customer data. Also defined an auxiliary array Customer *pData.

The program uses these parameters to sorts the array of pointers so that when you go through pData in increasing order of index k, the entries pData[k] point to Customer objects in decreasing order by balance, meaning that pdata[0] now points to the customer with the highest balance, and pData[9] points to the customer with the smallest balance.

4 0
2 years ago
An argument does not always have to be made in words. A piece of music
mixas84 [53]

Answer:

B. emotional

Explanation:

An emotional argument. An argument does not always have to be made in words.

4 0
3 years ago
Create pseudocode that could be used as a blueprint for a program that would do the following: An employer wants you to create a
mestny [16]

Answer:

START LOOP FOR EACH EMPLOYEE:

   INPUT employee’s name, hourly rate of pay, number of hours worked, overtime pay rate, payroll deductions, tax rate

   SET gross pay = (hourly rate of pay x *weekly hours) + (overtime pay rate x (number of hours worked - *weekly hours))

   PRINT gross pay

   SET net pay = gross pay - (payroll deductions + (gross pay * tax rate/100 ))

   PRINT net pay

END LOOP

* weekly hours (how many hours an employee needs to work to earn overtime pay rate) is not given in the question

Explanation:

Create a loop that iterates for each employee

Inside the loop, ask for name, hourly rate, number of hours worked, overtime pay rate, payroll deductions, tax rate. Calculate the gross pay and print it. Calculate the net pay and print it

8 0
3 years ago
Fifty-three percent of U.S households have a personal computer. In a random sample of 250 households, what is the probability th
aleksley [76]

Answer:

The correct Answer is 0.0571

Explanation:

53% of U.S. households have a PCs.

So, P(Having personal computer) = p = 0.53

Sample size(n) = 250

np(1-p) = 250 * 0.53 * (1 - 0.53) = 62.275 > 10

So, we can just estimate binomial distribution to normal distribution

Mean of proportion(p) = 0.53

Standard error of proportion(SE) =  \sqrt{\frac{p(1-p)}{n} } = \sqrt{\frac{0.53(1-0.53)}{250} } = 0.0316

For x = 120, sample proportion(p) = \frac{x}{n} = \frac{120}{250} = 0.48

So, likelihood that fewer than 120 have a PC

= P(x < 120)

= P(  p^​  < 0.48 )

= P(z < \frac{0.48-0.53}{0.0316}​)      (z=\frac{p^-p}{SE}​)  

= P(z < -1.58)

= 0.0571      ( From normal table )

6 0
3 years ago
Write a JavaScript statement to convert "Information Technology" to uppercase.
OLEGan [10]

Answer:

The JavaScript  statement is

var str1 =    "Information Technology";

var result = str1.toUpperCase();

Explanation:

JavaScript  is used to validate the client side it means it provide the client side validation.

Following are the function of JavaScript that converted the string into uppercase.

 function val()

{

 var str1 = "Information Technology ";

 var result = str1.toUpperCase();

}

The toUpperCase() function convert the string into uppercase in JavaScript

OUTPUT  

INFORMATION TECHNOLOGY

4 0
2 years ago
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