Where is
The pic? For the question for me to answer it
Answer:
a) 2.00 × 10¹⁰; b) 2.00 × 10¹³
Step-by-step explanation:
a) No. of cells in 1 cm³

b) No. of cells in 1 L

That would be

, but it is also equal to just

. You would simplify the

part, and you would get

, or if you need a decimal,

But don't forget the negative part, so the answer would be

or
Done u so like lengthy times width orr sum?
512 pounds
hope this helps