Answer:
x= 58
Step-by-step explanation:
minus 44 from 102
Answer: The approximate area of the circle is: <span>3,629.84 cm² .</span>
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Area of a circle, "A" : A = π * r² ;
in which: A = Area of circle ;
π <span>≈ 3.14 ;
</span> r = radius;
radius of a circle, "r" = d / 2 ; in which: "d = diameter" ;
Given "d = 64 cm " ;
r = d / 2 = 64 cm / 2 = 32 cm ;
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So; A = π * r² ;
A ≈ (3.14) * (32 cm)² ;
A ≈ (3.14) * (1156 cm²) ;
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A ≈ 3,629 .84 cm² .
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Answer:
See attached
Step-by-step explanation:
Given function:
Table and graph are attached
Zeros are included in the graph
<u>Zero's are obtained:</u>
x = 0 ⇒ y = 8
y = 0 ⇒ Solving quadratic equation
- -2x² + 5x + 8 = 0
- x = (-5 ± √(25 + 2*4*8))/-4
- x = 3.608
- x = -1.108
So zeros are (0, 8), (3.608, 0) and (-1.108, 0)
Answer:

Step-by-step explanation:
Ok, so first substitute x for 4 in
"g(x) = 5x + 1", and x for 3 in
"k(x) = 2/x + 2x". Now you got:
g(4) = 5(4) + 1
k(3) = 2/(3) + 2(3)
Now you can solve each individually.
g(4) = 5 × 4 = 20
20 + 1 = 21
g(4) = 21
k(3) = 2 × 3 = 6
6 + 2/3 = 6 2/3
k(3) = 6 2/3
g(4) + k(3) = 21 + 6 2/3 = <u>27 2/3</u>
Hope this helps :)
9514 1404 393
Answer:
(-2, 2)
Step-by-step explanation:
The orthocenter is the intersection of the altitudes. The altitude lines are not difficult to find here. Each is a line through the vertex that is perpendicular to the opposite side.
Side XZ is horizontal, so the altitude to that side is the vertical line through Y. The x-coordinate of Y is -2, so that altitude has equation ...
x = -2
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Side YZ has a rise/run of -1/1 = -1, so the altitude to that side will be the line through X with a slope of -1/(-1) = 1. In point-slope form, the equation is ...
y -(-1) +(1)(x -(-5))
y = x +4 . . . . . . . . subtract 1 and simplify
The orthocenter is the point that satisfies both these equations. Using the first equation to substitute for x in the second, we have ...
y = (-2) +4 = 2
The orthocenter is (x, y) = (-2, 2).