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2 years ago

Aiden is a percussionist in his

Mathematics

1 answer:

Bond [772]2 years ago

6 0

Answer:

could you show the triangle?

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Store a sells 12 bottles of water for 3.36 store b sells 24 bottles of water for 6.00 How much more Willa customer pay for 48 bo

Nataly_w [17]

Answer:

$1.44

Step-by-step explanation:

Store A:

12 bottles of water for $3.36

Then

48 bottles of water for $\$3.36\cdot 4=\$13.44$ (48 bottles is 4 times greater than 12 bottles)

Store B:

24 bottles of water for $6.00

Then

48 bottles of water for $\$6.00\cdot 2=\$12$ (48 bottles is twice greater than 24 bottles)

Difference:

$\$13.44-\$12=\$1.44$

6 0

3 years ago

2 7/9 × 1 1/5 ÷ 2 1/2

Anna007 [38]

Answer

5/36 ( $\frac{5}{36}$ )

7 0

3 years ago

Read 2 more answers

Is x^-2 -1 a polynomial

Bond [772]

Answer:

Yes, it is a polynomial.

Step-by-step explanation:

3 0

2 years ago

In the solution, 3b + 9c = 3(b + 3). What should be done to make it CORRECT?

stiks02 [169]

Answer:

The second term of the binomial factor should be 3c instead of 3.

Step-by-step explanation:

Distributive property:

a*b + a*c = a*(b +c)

3b + 9c = 3*b + 3* 3 *c = 3*(b + 3c)

7 0

3 years ago

Determine what shape is formed for the given coordinates for ABCD, and then find the perimeter and area as an exact value and ro

Helga [31]

Answer:

Part 1) The shape is a trapezoid

Part 2) The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

Part 3) The area is $937.5\ units^2$

Step-by-step explanation:

step 1

Plot the figure to better understand the problem

we have

A(-28,2),B(-21,-22),C(27,-8),D(-4,9)

using a graphing tool

The shape is a trapezoid

see the attached figure

step 2

Find the perimeter

we know that

The perimeter of the trapezoid is equal to

$P=AB+BC+CD+AD$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

we have

A(-28,2),B(-21,-22)

substitute in the formula

$d=\sqrt{(-22-2)^{2}+(-21+28)^{2}}$

$d=\sqrt{(-24)^{2}+(7)^{2}}$

$d=\sqrt{625}$

$d_A_B=25\ units$

Find the distance BC

we have

B(-21,-22),C(27,-8)

substitute in the formula

$d=\sqrt{(-8+22)^{2}+(27+21)^{2}}$

$d=\sqrt{(14)^{2}+(48)^{2}}$

$d=\sqrt{2,500}$

$d_B_C=50\ units$

Find the distance CD

we have

C(27,-8),D(-4,9)

substitute in the formula

$d=\sqrt{(9+8)^{2}+(-4-27)^{2}}$

$d=\sqrt{(17)^{2}+(-31)^{2}}$

$d=\sqrt{1,250}$

$d_C_D=25\sqrt{2}\ units$

Find the distance AD

we have

A(-28,2),D(-4,9)

substitute in the formula

$d=\sqrt{(9-2)^{2}+(-4+28)^{2}}$

$d=\sqrt{(7)^{2}+(24)^{2}}$

$d=\sqrt{625}$

$d_A_D=25\ units$

Find the perimeter

$P=25+50+25\sqrt{2}+25$

$P=(100+25\sqrt{2})\ units$

simplify

$P=25(4+\sqrt{2})\ units$ ----> exact value

$P=135.4\ units$

therefore

The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

step 3

Find the area

The area of trapezoid is equal to

$A=\frac{1}{2}[BC+AD]AB$

substitute the given values

$A=\frac{1}{2}[50+25]25=937.5\ units^2$

4 0

3 years ago