a. Given that y = f(x) and f(0) = -2, by the fundamental theorem of calculus we have

Evaluate the integral to solve for y :



Use the other known value, f(2) = 18, to solve for k :

Then the curve C has equation

b. Any tangent to the curve C at a point (a, f(a)) has slope equal to the derivative of y at that point:

The slope of the given tangent line
is 1. Solve for a :

so we know there exists a tangent to C with slope 1. When x = -1/3, we have y = f(-1/3) = -67/27; when x = -1, we have y = f(-1) = -3. This means the tangent line must meet C at either (-1/3, -67/27) or (-1, -3).
Decide which of these points is correct:

So, the point of contact between the tangent line and C is (-1, -3).
Answer:
The correct answer is option D. 4
Step-by-step explanation:
Points to remember
Opposite sides of the parallelogram are equal.
From the figure we can see that,AB and CD are opposite sides.
Therefore AB = CD
<u>To find the length of AB</u>
From the figure we get, AB = 4 units
Therefore CD = 4 units
<u>To find the x coordinate of point C</u>
y coordinate is -1
x coordinate is 4 units from point D
x coordinate of D is 0, therefore x coordinate of C = 0 + 4 = 4
The correct answer is option D. 4
With every imaginary term, there are 2 complex conjugates with opposing signs. So if I had the term a+bi, the complex conjugate would be a-bi. So given your example of -1+4i, the complex conjugate would just be the opposite sign, now negative, to get -1-4i.
Answer:1331cm
Step-by-step explanation:vol=lbh
11*11*11cm=1331cm