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3 years ago

Which of the following values are in the range of the function graph below check all that apply

Mathematics

1 answer:

Ivanshal [37]3 years ago

6 0

It is
A, C, D, and E

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What is the depth and volume of this rectangular prism in cubes and cubic inches?

Inessa05 [86]

Height = 3 cubes
Width = 5 cubes
Depth = 4 cubes

Number of Cubes = 3*4*5 = 60

Each cube is .2 inches on each side

So, it's volume = 1 * .6 * .8 = .48 cubic inches

Double - Check
Each cube is .2*.2*.2 = 0.008 cubic inches
There are 60 cubes so the volume =
60 * .008 = .48 cubic inches CORRECT !!

6 0

3 years ago

If f(x)=x-6 and g(x)=x1/2(x+3), find g(x) times f(x)

Elden [556K]

To solve this problem you must apply the proccedure shown below:
1. You have the following functions given in the problem above:
$f(x)=x-6 
$ and $g(x)=x1/2(x+3)=x(x+3)/2$ 
2. You have that g(x) times f(x) can be written as g(x)*f(x). Therefore, you must multiply f(x) * g(x), as following:
 $g(x)*f(x)=(x-6)*x(x+3)/2$ 
3. Applying the distributive property, you have:
 $g(x)*f(x)=( x^{3} + 3x^2 - 6x^{2} -18x)/2$
$g(x)*f(x)=(x^{3} - 3x^{2} -18x)/2$
The answer is: $g(x)*f(x)=(x^{3} - 3x^{2} -18x)/2$

5 0

3 years ago

Suppose that 50% of all young adults prefer McDonald's to Burger King when asked to state a preference. A group of 12 young adul

ddd [48]

Answer:

a) 0.194 = 19.4% probability that more than 7 preferred McDonald's

b) 0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred McDonald's

c) 0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred Burger King

Step-by-step explanation:

For each young adult, there are only two possible outcomes. Either they prefer McDonalds, or they prefer burger king. The probability of an adult prefering McDonalds is independent from other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

50% of all young adults prefer McDonald's to Burger King when asked to state a preference.

This means that $p = 0.5$

12 young adults were randomly selected

This means that $n = 12$

(a) What is the probability that more than 7 preferred McDonald's?

$P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{12,8}.(0.5)^{8}.(0.5)^{4} = 0.121$

$P(X = 9) = C_{12,9}.(0.5)^{9}.(0.5)^{3} = 0.054$

$P(X = 10) = C_{12,10}.(0.5)^{10}.(0.5)^{2} = 0.016$

$P(X = 11) = C_{12,11}.(0.5)^{11}.(0.5)^{1} = 0.003$

$P(X = 12) = C_{12,12}.(0.5)^{12}.(0.5)^{0} = 0.000$

$P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) = 0.121 + 0.054 + 0.016 + 0.003 + 0.000 = 0.194$

0.194 = 19.4% probability that more than 7 preferred McDonald's

(b) What is the probability that between 3 and 7 (inclusive) preferred McDonald's?

$P(3 \leq X \leq 7) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.054$

$P(X = 4) = C_{12,4}.(0.5)^{4}.(0.5)^{8} = 0.121$

$P(X = 5) = C_{12,5}.(0.5)^{5}.(0.5)^{7} = 0.193$

$P(X = 6) = C_{12,6}.(0.5)^{6}.(0.5)^{6} = 0.226$

$P(X = 7) = C_{12,7}.(0.5)^{7}.(0.5)^{5} = 0.193$

$P(3 \leq X \leq 7) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) = 0.054 + 0.121 + 0.193 + 0.226 + 0.193 = 0.787$

0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred McDonald's

(c) What is the probability that between 3 and 7 (inclusive) preferred Burger King?

Since $p = 1-p = 0.5$ , this is the same as b) above.

0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred Burger King

7 0

3 years ago

When it hatches from its egg, the shell of certain crab is 1cm across. When fully grown the shell is approximately 10cm across.

inn [45]

Well every time it gets rid of a shell it grows 1 1/3 times larger. So so to see how much it grows after the first time you say
1 cm * 1 1/3 = 1 1/3 cm

to get the next one you do the same
1 1/3 cm * 1 1/3 cm = 16/9

It will keep going multiplying by 1 1/3. So so we can say in an equation that the
(initial size) * 1 1/3 *(number of shells) = length

Or 1cm * 1 1/3 * n = L

We we know the final length is 10cm

So 1 1/3 * n = 10cm

n = 7.5shells

so approximately 7 or 8 shells

8 0

3 years ago

Sketch a 3 by y square. Find its area in terms of y show your reasoning

user100 [1]

Well it says SQUARE so in a square all sides are equivalent so it will be 3x3 and that will hy your answer (y=3)

7 0

3 years ago