Answer:
diamerer of the hair (t) 3.11 X 10^{-5} m
Step-by-step explanation:
The first dark spot is at the zero location where the glass plates touch. To find the number of dark fringes after first dark fringe, divide 12 cm by 0.75 mm (.075 cm)
12/.075 = 160.0
total number of additional bright fringe is 156 because there is no further portion for extra dark fringe.
diamerer of the hair (t) can be derived as
2nt = (m + .5)*wavelength
2(1.52)(t) = (160.5)(589.3 X 10^{-9})
t = 3.11 X 10^{-5} m
The Length of FD = 26 cm
According to the given information
FE = FC = 12cm
As FE, FC both are radius of circle
The tangent segments to a circle from a external point are equal
Hence
CD = ED
13x - 16 = 4x + 11
13x - 4x = 11 + 16
9x = 27
x = 27/9
x = 3
CD = 13x - 16
= 13 × 3 - 16
= 23 cm
ED = 4x + 11
= 4 × 3 + 11
= 23 cm
In Triangle FED
FE is perpendicular to ED
According to Pythagoras Theorem
= 
= 673
FD = 26 cm approx.
The Length of FD = 26 cm
To know more about Pythagoras Theorem
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if a b 9 are in GP
b÷a = 9 ÷ b
b^2 = 9a
if a - 1 b 9 are in AP
2b = a+8
b = a+8÷2
substitute
b is equal to a + 8 by 2 in b square equal to 9 a
(a+8÷2)^2 = 9a
a^2+16a+64 = 36a
a^2 -20a +64 =0
(a-16) (a-4) =0
a= 16 or a=4
when a=16 b= 12
when a=4 b= 6
Value of a and b are given above
Answer:The cost of one month of game-play =$20
Step-by-step explanation:
Let the cost of one month of gameplay be x
Then cost of game-play bought by Angie =3x.....(1)
and Then cost of game-play bought by Kenny=4x......(2)
Cost of each software package =$50......(3)
The the total cost =240= sum of costs of software bought by both of them and game-play)=50+50+3x+4x
⇒240=100+7x.......→(by adding like terms)
⇒140=7x⇒x=20.....→( dividing both sides by 7 )
∴the cost of one month of game-play =$20
Answer:
-1/6
Step-by-step explanation:
-1/2 + ( 3/4 x 4/9)
PEMDAS says parentheses first
Rearranging the fractions
-1/2 + ( 3/9 x 4/4)
-1/2 + (1/3*1)
-1/2 + 1/3
Getting a common denominator of 6
-1/2 *3/3 + 1/3 *2/2
-3/6+2/6
-1/6
