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Lelechka [254]
3 years ago
6

PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!! I CANNOT RETAKE THIS!!

Mathematics
1 answer:
gavmur [86]3 years ago
6 0

\text{Use}\\\\a^2-b^2=(a-b)(a+b)\\\\i=\sqrt{-1}\to i^2=-1\\---------------------\\\\x^2+25=x^2+5^2=x^2-(-1)(5^2)=x^2-(i^2)(5^2)=x^2-(5i)^2\\\\\boxed{x^2+25=(x-5i)(x+5i)}

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