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Vadim26 [7]
2 years ago
15

Answer pls and ill give you brainlliest

Mathematics
2 answers:
vfiekz [6]2 years ago
6 0

Answer:

50%

Step-by-step explanation:

because ther are 2 even and 2 odd

posledela2 years ago
5 0

you have 4 fields where it can land, so the probability has a denominator 4.

2 of those fields have a even number so the numerator is 2.

-> probability is 2/4= 1/2

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Find the sum of the positive integers less than 200 which are not multiples of 4 and 7​
taurus [48]

Answer:

12942 is the sum of positive integers between 1 (inclusive) and 199 (inclusive) that are not multiples of 4 and not multiples 7.

Step-by-step explanation:

For an arithmetic series with:

  • a_1 as the first term,
  • a_n as the last term, and
  • d as the common difference,

there would be \displaystyle \left(\frac{a_n - a_1}{d} + 1\right) terms, where as the sum would be \displaystyle \frac{1}{2}\, \displaystyle \underbrace{\left(\frac{a_n - a_1}{d} + 1\right)}_\text{number of terms}\, (a_1 + a_n).

Positive integers between 1 (inclusive) and 199 (inclusive) include:

1,\, 2,\, \dots,\, 199.

The common difference of this arithmetic series is 1. There would be (199 - 1) + 1 = 199 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times ((199 - 1) + 1) \times (1 + 199) = 19900 \end{aligned}.

Similarly, positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 4 include:

4,\, 8,\, \dots,\, 196.

The common difference of this arithmetic series is 4. There would be (196 - 4) / 4 + 1 = 49 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 49 \times (4 + 196) = 4900 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 7 include:

7,\, 14,\, \dots,\, 196.

The common difference of this arithmetic series is 7. There would be (196 - 7) / 7 + 1 = 28 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 28 \times (7 + 196) = 2842 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 28 (integers that are both multiples of 4 and multiples of 7) include:

28,\, 56,\, \dots,\, 196.

The common difference of this arithmetic series is 28. There would be (196 - 28) / 28 + 1 = 7 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 7 \times (28 + 196) = 784 \end{aligned}.

The requested sum will be equal to:

  • the sum of all integers from 1 to 199,
  • minus the sum of all integer multiples of 4 between 1\! and 199\!, and the sum integer multiples of 7 between 1 and 199,
  • plus the sum of all integer multiples of 28 between 1 and 199- these numbers were subtracted twice in the previous step and should be added back to the sum once.

That is:

19900 - 4900 - 2842 + 784 = 12942.

8 0
3 years ago
If 3x - 8= -2, find the value of x - 6.
siniylev [52]

Answer:

x-6 = -4

Step-by-step explanation:

3x - 8= -2

Add 8 to each side

3x - 8+8= -2+8

3x = 6

Divide by 3

3x/3 = 6/2

x =2

We want to find x-6

2-6 = -4

4 0
3 years ago
Read 2 more answers
Sum of exterior angles in a polygon?
soldi70 [24.7K]

Answer:

360

Step-by-step explanation:

The exterior angles always add up to 360 in a polygon because it's the sum of all the vertexes which would make a circle.

8 0
3 years ago
Can someone PLease help me, Please please
Molodets [167]
The triangle on the left appears to be congruent with the triangle on the right.  If this observation is actually valid, then x+7 = 2x-5.  12=x  Yes, I realize that this doesn't match any of the answer choices, 'tho the 4th choice is the only one that contains "12."  Would you please share the instructions for this problem.

3 0
3 years ago
Which function is the inverse of f(x) = 2x+37
WINSTONCH [101]

Answer:

f^{-1} (x)=\frac{x-3}{2}

Step-by-step explanation:

y = f(x)

y = 2x+3

You need to switch the places of x and y, into this:

x = 2y + 3

Then solve for y:

2y = x-3

y=\frac{x-3}{2}

f^{-1} (x)=\frac{x-3}{2}

3 0
3 years ago
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