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2 years ago

Priya's favorite singer has made 6 albums containing 75 songs in total. Priya wants to make a playlist of 10 of

Mathematics

1 answer:

Sliva [168]2 years ago

4 0

The appropriate values of n and r are illustrations of permutation.

The values of n and r are 75 and 10, respectively

<h3>How to determine the appropriate values of n and r?</h3>

From the question, we have the following parameters:

Albums = 6
Total songs = 75
Songs to arrange in a album = 10

The above means that:

n = 75

r = 10

This can be interpreted as:

Arrange 10 songs from a list of 75 songs

Hence, the appropriate values of n and r are 75 and 10, respectively

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How many units of a 10% solution are needed to prepare 500 units of a 2% solution?

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First find how many units of solution there is:

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3 years ago

An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed

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Answer:

$P(X\leq 1) = 0.331$

Step-by-step explanation:

Given

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Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

$P(X = x) = \frac{y^xe^{-y}}{x!}$

Where y represents λ (average)

y = 2.3

<em>Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment</em>

<em />

Using probability notations;

$P(X\leq 1) = P(X=0) + P(X =1)$

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

$P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}$

$P(X = 0) = \frac{1 * e^{-2.3}}{1}$

$P(X = 0) = e^{-2.3}$

$P(X = 0) = 0.10025884372$

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

$P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}$

$P(X = 1) = \frac{2.3 * e^{-2.3}}{1}$

$P(X = 1) =2.3 * e^{-2.3}$

$P(X = 1) = 2.3 * 0.10025884372$

$P(X = 1) = 0.23059534055$

$P(X\leq 1) = P(X=0) + P(X =1)$

$P(X\leq 1) = 0.10025884372 + 0.23059534055$

$P(X\leq 1) = 0.33085418427$

$P(X\leq 1) = 0.331$

Hence, the required probability is 0.331

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Lapatulllka [165]

372819388338822814738288919147477483822 okay i guess

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