Factor the equation to give



By the zero product property, either x^2=0 or (3x^2+12-6x)=0 or both.
If x^2=0, then x=0
if (3x^2+12-6x)=0, we use the quadratic formula to solve for x
where x=1 ± √ (3) i
Answer: the roots of <span>3x^4+12x^2=6x^3 are {0 (multiplicity 2), 1+√3 i, 1-√3 i}</span>
2 bags, because when you add 5/8 and 1 3/8 you get 1 8/8 which is really 2
Answer:
Step-by-step explanation:
a number no less then 15
let the number be x
no less then 15....means it has to be 15 or more
x > = 15 (thats greater then or equal to)
Since the argument of the sine function is x without any scaling factor, the period is 2π, the 1st selection.