The location of the y value of R' after using the translation rule is -10
<h3>What will be the location of the y value of R' after using the translation rule? </h3>
The translation rule is given as:
(x + 4, y - 7)
The pre-image of R is located at (-17, -3)
Rewrite as
R = (-17, -3)
When the translation rule is applied, we have:
R' = (-17 + 4, -3 - 7)
Evaluate
R' = (-13, -10)
Remove the x coordinate
R'y = -10
Hence, the location of the y value of R' after using the translation rule is -10
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Answer:
when reflected across the y-axis the points will reflect onto the other side on the y-axis.
when reflected over the x-axis the points with reflect onto the x-axis
Answer:
x = 5
Step-by-step explanation:
The formula for the gradient is given by:
m = (y2 - y1)/(x2 - x1), where two points (x1, y1) and (x2, y2) are given.
Thus if we have a gradient of 2.5 and two points (3, 8) and (x, 13), we can substitute this into the above formula for the gradient to get:
2.5 = (13 - 8)/(x - 3)
2.5(x - 3) = 5 (Multiply both sides by (x - 3))
x - 3 = 2 (Divide both sides by 2.5)
x = 5 (Add 3 to both sides)
Thus, the value of x is 5.
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U would factor by grouping and get x^2(x-2) + 3(x-2) and then get (x^2 +3) (x-2)